Answer:
1
Step-by-step explanation:
I not completely sure but I think it 1
Answer:
Option (3)
Step-by-step explanation:
Glide reflection of a figure is defined by the translation and reflection across a line.
To understand the glide rule in the figure attached we will take a point A.
Coordinates of the points A and A' are (2, -1) and (-2, 4).
Translation of pint A by 5 units upwards,
Rule to be followed,
A(x, y) → A"[x, (y + 5)]
A(2, -1) → A"(2, 4)
Followed by the reflection across y-axis,
Rule to be followed,
A"(x, y) → A'(-x, y)
A"(2, 4) → A'(-2, 4)
Therefore, by combining these rules in this glide reflections of point A we get the coordinates of the point point A'.
Option (3) will be the answer.
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The normal vectors to the two planes are (3, 3, 2) and (2, -3, 2). The cross product of these will be the direction vector of the line of intersection, (12, -2, -15).
Using x=0, we can find a point on this line by solving the simultaneous equations that remain:
... 3y +2z = -2
... -3y +2z = 2
Adding these, we get
... 4z = 0
... z = 0
so the point we're looking for is (x, y, z) = (0, -2/3, 0). This gives rise to the parametric equations ...
- x = 12t
- y = -2/3 -2t
- z = -15t
By letting t=2/3, we can find a point on the line that has integer coefficients. That will be (x, y, z) = (8, -2, -10).
Then our parametric equations can be written as
- x = 8 +12t
- y = -2 -2t
- z = -10 -15t