Hope this is the right one.
Problem 8p^2 - 30p + c
<em>Step One</em>
Take 1/2 of - 30
1/2 * -30 = - 15
<em>Step 2
</em>Square -15
(-15)^2 = 225
c = 225
Problem Ninea = 1
b = 4
c = -15
x = [-4 +/- sqrt(76)] / 2
x = [-4 +/- 2*sqrt19]/2
x = [-4/2 +/- 2/2 sqrt[19]
x = - 2 +/- sqrt(19)
x1 = - 2 + sqrt(19)
x2 = -2 - sqrt(19)
These two can be broken down more by finding the square root. I will leave them the way they are. It's just a calculator question if you want it to go into decimal form.
Problem Tena = 1
b = 4
c = -32
The discriminate is sqrt(b^2 - 4ac)
D = sqrt(b^2 - 4ac)
D = sqrt(4^2 - 4(1)(-32)
D = sqrt(16 - - 128)
D = sqrt(16 + 128)
D = sqrt(144)
D = +/- 12
Since D can equal + or minus 12 there must be 2 possible (and different) roots. As a matter of fact, this quadratic can be factored.
(x + 8)(x - 4) = y
But that' s not what you were asked for.
The discriminate is > 0 so the roots are going to be real.
<em>
Answer; The discriminate is > 0 so there will be 2 real different roots.</em>
Answer:
I am not sure honestly, but I think you should
Step-by-step explanation:
add 2,200 and 3,000 then see your answer, and divide it by 125. I'm sorry if this doesn't help......
If the Length is 11 and the Width is 3 that makes the area 33. Now if you want all possible answers less than 33 then:
L: W: A:
11cm 3cm = 33cm
10cm 2cm = 20cm
9cm 1cm = 9cm
Now that's as low as you can get with whole numbers.
Answer:
It has no special appearance.
Step-by-step explanation:
Any angle of measure 180° or less is supplementary to some angle. A supplementary angle is one that is the difference between 180° and the angle you have. That is, two supplementary angles total 180°.
__
Supplementary angles are readily identifiable in a number of geometries. Adjacent angles of a parallelogram are supplementary; linear angles are supplementary. Same-side interior angles where a transversal crosses parallel lines are supplementary.
Answer:
Teo is 11 years old and Richard is 26 years old.
Step-by-step explanation:
Let R be the age of Richard and T be the age of Teo.
<u><em>First set up the equations:</em></u>
The combined age of Teo and Richard is 37:
R+T=37
Richard is four years old than twice Teo's age:
R=2T+4
<u><em>Then, solve the equations:</em></u>
Substitute (2) to (1) and solve for T:
(2T+4)+T=37
3T=11
T=11
Solve for R using (2):
R=2(11)+4
R=22+4
R=26