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BabaBlast [244]
3 years ago
14

One postive interger is 5 less than another. The product of the two intergerd id 24. What are the intergers?

Mathematics
1 answer:
Nesterboy [21]3 years ago
4 0
Your function will be 24=X+(Y+5)

to solve you subtract 5 from each side giving you 19=X+Y now you divide the 19 by 2 so you figure out the base integers giving you 9.5

now you add 5 to one of your integers meaning 9.5+5=14.5

so your integers are 9.5 and 14.5

to check this you do 14.5-9.5 which equal 5 now you do 14.5+9.5 which equals 24
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The exponents are subtracted one from another when divided.
\frac{ a ^{b} }{ {a}^{c} } =  {a}^{b - c}
We can look at the problem this way:
( \frac{6^{7} }{6 ^{6} }  \times  \frac{3^{3} }{ {3}^{4} } ) = (6^{7 - 6}  \times  {3}^{3 - 4} ) =  \\ ({6}^{1}  \times  {3}^{ - 1} )
Since we have the power of -1 on the 3, we apply this rule:
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Then we get this:
(6 \times  \frac{1}{3} )^{3}  = ( \frac{6}{3} )^{3}
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\frac{{6}^{3} }{ {3}^{3} } =  \frac{216}{27}  = 8
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