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lana [24]
3 years ago
11

What are the most important benefits of using Virtual Reality in business training?.

Computers and Technology
2 answers:
Effectus [21]3 years ago
8 0

Answer:

If something goes wrong, it doesn't affect any real-world situations or the company itself in the real world

Explanation:

maw [93]3 years ago
5 0

The most important benefit of using virtual reality in business training is that it reduces the risk and cost of any damage. It also provides safety to the business.

<h3>What is virtual reality?</h3>

Virtual reality is a computer-generated simulation that is similar to the real environment but actually, it is not. It provides an imaginary environment based on the requirements.

Business training is the process in which all the aspects of a business or an organisation are discussed and elaborated. It is essential for the understanding and growth of a business. In the current world, virtual reality plays an important role in training as it enhances the efficiency of the training.

Following are the advantages of using virtual reality in business training:

  • It accelerates the speed of training.
  • It reduces onboarding time.
  • It reduces interruptions in business.
  • It reduces the risks.
  • It reduces the cost of damage.
  • It improves the safety of the workspace.

Learn more about virtual reality here:

brainly.com/question/26108771

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Which solution eliminates the need for dedicated high-speed WAN connections between sites
s344n2d4d5 [400]

Answer:

running in the 90 s intensifies

Explanation:

4 0
3 years ago
7.12 LAB: Even/odd values in a list
Korvikt [17]

The odd values in a list can be calculated by knowing the first and last number, whereas even numbers can be divided by two and the remainder is zero (0).

<h3>What are even numbers and odd numbers?</h3>

The even numbers can be found in a list because they are divisible by two and the remainder of this equation is always zero (0).

Conversely, odd numbers are those that cannot be divided exactly into exact entire numbers (e.g., 3, 5, etc).

The odd numbers in a list can be calculated by the equation ON (odd numbers): n/2 × [f + g], where 'f' is the first number and 'g' is the last number.

In conclusion, the odd values in a list can be calculated by knowing the first and last number, whereas even numbers can be divided by two and the remainder is 0.

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brainly.com/question/2263958

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4 0
2 years ago
What type of storage drive contains multiple spinning platters?
Gala2k [10]

The type of storage drive that contains multiple spinning platters is called; Hard disk drives

<h3>What is the hard disk drive?</h3>

A computer hard disk drive (HDD) is a non-volatile data storage device. Non-volatile refers to storage devices that maintain stored data when turned off.

Now, the correct answer to the question is hard disk drives. This is because a hard disk drive is comprised of a stack of spinning metal disks known as platters. Each spinning disk has trillions of tiny fragments that could possibly be magnetized in order to represent bits (1s and 0s in binary code).

Read more about Hard disk drives at; brainly.com/question/24498473

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8 0
2 years ago
How do multi-cellular organisms develop?
FromTheMoon [43]
Letter B. is the answer
<span>B.  Cell differentiation - start from a single cell and as the cells divide they become specialized</span>

HOPE THIS HELPS















4 0
3 years ago
Hello again, just need help debugging-I honestly have no idea how the "isSpace" etc methods work and I've tried various syntaxes
Julli [10]

import java.util.Scanner;

public class JavaApplication81 {

   

   public static void main(String[] args) {

       Scanner s = new Scanner(System.in);

       System.out.println("Input the string");

       String as = s.nextLine();

       int cons = 0;

       int a = 0;

       int e = 0;

       int i = 0;

       int o = 0;

       int u = 0;

       int space = 0;

       int punc = 0;

       char c;

       int misc = 0;

       String punctuation = ".!,?";

       String consonants = "bcdfghjklmnpqrstvwxyz";

       for (int k = 0; k < as.length(); k++){

           c = as.charAt(k);

       if (Character.isWhitespace(c)){

           space ++;

       }

       else if (punctuation.indexOf(c) != -1){

           punc++;

       }

       else if (consonants.indexOf(c) != -1){

           cons++;

       }

       else if (c == 'a'){

           a++;

       }

       else if(c == 'e'){

           e++;

       }

       else if (c == 'i'){

           i++;

       }

       else if (c == 'o'){

           o++;

       }

       else if (c == 'u'){

           u++;

       }

       else{

           misc++;

       }

       

   }

       System.out.println(a+" a's");

       System.out.println(e+" e's");

       System.out.println(i+" i's");

       System.out.println(o+" o's");

       System.out.println(u+" u's");

       System.out.println(space+" spaces");

   

       System.out.println(punc+" punctuations");

       System.out.println(cons+" consonants");

       System.out.println(misc+" misc. (uppercase vowels, etc.");

   }

   

}

This is one example of how it could be done.

5 0
3 years ago
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