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2 answers:
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Answer:
See explanation
Step-by-step explanation:
In equilateral ∆ABC,
Points M, P, and K belong to AB , BC , and AC respectively and
AM:MB = BP:PC = CK:KA = 1:3.
So,
Triangles AMK, BPM and CKP are all congruent by SAS postulate, so
If triangle MPK is equilateral triangle
