Answer:
scdeceece
Step-by-step explanation:
rfqscf
8-2(n+3)=n+7-3n
We move all terms to the left:
8-2(n+3)-(n+7-3n)=0
We add all the numbers together, and all the variables
-2(n+3)-(-2n+7)+8=0
We multiply parentheses
-2n-(-2n+7)-6+8=0
We get rid of parentheses
-2n+2n-7-6+8=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
Answer:
A. (x + 2)^2 = 31.
Step-by-step explanation:
x^2 + 4x = 27
x^2 + 4x - 27 = 0
A. (x + 2)^2 = 31
x^2 + 4x + 4 - 31 = 0
x^2 + 4x - 27 = 0
This option corresponds to the given equation, so it is correct.
B. (x + 2)^2 = 43
x^2 + 4x + 4 - 43 = 0
x^2 + 4x - 39 = 0
This does not correspond to the equation.
C. (x + 4)^2 = 31
x^2 + 8x + 16 - 31 = 0
x^2 + 8x - 15 = 0
This does not correspond to the equation.
D. (x+4)^2 = 43
x^2 + 8x + 16 - 43 = 0
x^2 + 8x - 27 = 0
This does not correspond to the equation.
So, your answer is A. (x + 2)^2 = 31.
Make sure to SUBMIT and check your PREVIOUS answers to make sure they are right! XD Also, hope this helps!
Answer: ![f^{-1}(x) = \frac{\sqrt[3]{x^{2}}}{x}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%7D%7D%7Bx%7D)
<u>Step-by-step explanation:</u>
Inverse is when you swap the x's and y's and then solve for "y":
![y = \frac{1}{\sqrt[3]{x}}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D)
![y = \frac{1}{\sqrt[3]{x}}*(\frac{\sqrt[3]{x}}{\sqrt[3]{x}})^{2}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D%2A%28%5Cfrac%7B%5Csqrt%5B3%5D%7Bx%7D%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D%29%5E%7B2%7D)
![y = \frac{\sqrt[3]{x^{2}}}{x}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%7D%7D%7Bx%7D)
Answer:
bxbdbdbdbhd
Step-by-step explanation:
$2200jfjfjffjfodod/month
