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poizon [28]
2 years ago
12

A dog weighs 35.4 kilograms.1 kilogram=2.2 pounds,1 pound=0.45 kilograms.About how much does the dog weigh in pounds?Round to ne

arest Whole.
Mathematics
2 answers:
AlladinOne [14]2 years ago
4 0
Answer: 78 pounds
Explanation: if 1 kilogram is 2.2 pounds, just multiply the weight in kg by 2.2:
35.4 x 2.2 = 77.88
Round to nearest whole: 78.
So the dog is 78 pounds
wolverine [178]2 years ago
3 0

Answer:

78 pounds

Step-by-step explanation:

hope this helped

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A reading teacher recorded the number of pages read in an hour by each of her
Ymorist [56]

Answer:

the lower quartile should be 43.5, not 44, therefore the 3 is the wrong statistic

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
Your electric bill has been as follows for the past six months:
kakasveta [241]

You want to find the monthly average over the past 6 months.


July: $78.56

August: $30.21

September: $81.20

October: $79.08

November: $66.18

December: $100.75


Add all of these up

(July) $78.56

(August) $30.21

(September) $81.20

(October) $79.08

(November) $66.18

(December) + $100.75

----------------------------------------------

(Total cost) $435.88


There are 6 months you are calculating for, therefore divide the total (combined) cost of 6 months with the total number of months (in this case, 6)


$435.88 (total cost of 6 months) ÷ 6 (months)


The average cost per month of over the past 6 months is $72.66.

4 0
3 years ago
Read 2 more answers
3х 4 = 3<br><br>what is the value of x?​
lord [1]

Answer:

1/3

Step-by-step explanation:

transfer 4 to the other side then the sign will be minus

then divide 1 by 3

5 0
3 years ago
Read 2 more answers
Suppose that 20% of adults belong to health clubs, and 51% of these health club members go to the club at least twice a week. Wh
Westkost [7]

Answer:

10.2% of adults will belong to health clubs and will go to the club at least twice a week

Step-by-step explanation:

assuming that the event H=an adult belongs to a health  club  and the event T= he/she goes at least twice a week , then if both are independent of each other:

P(T∩H)= P(H)*P(T)  ( probability of the union of independent events → multiplication rule )

replacing values

P(T∩H)= P(H)*P(T) = 0.20 * 0.51 =0.102

then  10.2% of adults will belong to health clubs and will go to the club at least twice a week

5 0
3 years ago
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