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Eddi Din [679]
3 years ago
6

2х - 1y = 6 -Зу = -6х + 18

Mathematics
2 answers:
zysi [14]3 years ago
7 0

Answer:2x-y-6=0 & 2x-y=6

Step-by-step explanation:

-3y=-6x+18.

-3y+6x=18

-y+2x=6

2x-y=6

2x-1y=6

2x-y=6

2x-y-6=0

Elenna [48]3 years ago
4 0

Answer:

y=-6+2x

Step-by-step explanation:

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Need help ASAP please give answer in cm squared
MrRa [10]

Answer:

17×15=255

Step-by-step explanation:

you do base times height

5 0
3 years ago
Every 1/2 hour Naomi stretches her neck; every 1/3 hour she stretches her legs; and every 1/6 hour she stretches her arms. Which
Sav [38]
Legs and arms Reply if you need an explanation since tis should be right
6 0
2 years ago
Read 2 more answers
A department store has a discount on shoes based on percentage of the price. Suppose one pair of shoes is marked down 70$ to 49$
pentagon [3]
<span><span>1.       </span>A department store has a discount on shoes based on percentage of price.
=> one pair of shoes marked down from 70 dollars to 49  dollars
=> let’s solve for the percentage rate.
=> 70 – 49 = 21, the than ½ of the price
=> 70 x 30% = 21
Thus, the percentage rate is 30%
For the pair of shoes that is 110 dollars
=> 110 * .30 = 33
=> 110 – 33 = 77
Thus, the price of pair of shoes is now 77 dollars.</span>



8 0
3 years ago
The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe
UNO [17]

Answer:

The shark are fed \frac16 \ ton of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = \frac{2}{15}\ ton

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = \frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton

Total fish fed in whole day = \frac12 \ ton

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = \frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = \frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = \frac{3-2}{6}=\frac16 \ ton

Hence The shark are fed \frac16 \ ton of fish during the night.

3 0
3 years ago
carlos and Jacob each improve their yards by planting daylilies and ivy. They bought their supplies from the same stores. Carlos
34kurt

Answer:

Cost of each daylilies = $3

Cost of each ivy pot = $3

Step-by-step explanation:

Given:

Cost of 4 daylilies and 4 ivy = $24

Cost of 4 daylilies and 8 ivy = $36

Find:

Cost of each daylilies

Cost of each ivy pot

Computation:

Assume;

Cost of each daylilies = a

Cost of each ivy pot = b

So,

4a + 4b = 24....... eq 1

4a + 8b = 36 ....... eq 2

Eq2 - Eq1

8b - 4b = 36 - 24

4b = 12

b = 3

So,

Cost of each ivy pot = $3

4a + 4b = 24

4a + 4(3) = 24

4a + 12

a = 3

Cost of each daylilies = $3

6 0
3 years ago
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