<h3><em>In AP form 2nd term - 1st term = 3rd term - 2nd term
</em></h3><h3><em>b²-a² = c²-b²
</em></h3><h3><em>b²+b² = c²+a²
</em></h3><h3><em>2b² = c²+a²
</em></h3><h3><em>
</em></h3><h3><em>Add 2ab+2ac+2bc on both sides
</em></h3><h3><em>
</em></h3><h3><em>2b²+2ab+2ac+2bc = a²+c²+ac+ac+bc+bc+ab+ab
</em></h3><h3><em>2b²+2ab+2ac+2bc = ac+bc+a²+ab+bc+c²+ab+ac
</em></h3><h3><em>2b²+2ab+2ca+2cb = ca+cb+a²+ab+cb+c²+ab+ac
</em></h3><h3><em>2(ba+b²+ca+cb) = (ca+cb+a²+ab) + (cb+c²+ab+ac)
</em></h3><h3><em>2((ba+b²)+(ca+cb)) = ((ca+cb)+(a²+ab)) + ((cb+c²)+(ab+ac))
</em></h3><h3><em>2(b(a+b)+c(a+b)) = (c(a+b)+a(a+b)) + (c(b+c)+a(b+c)) </em></h3><h3><em>2(b+c)(a+b) = (c+a)(a+b) + (c+a)(b+c)
</em></h3><h3><em>
</em></h3><h3><em>Divide whole by (a+b)(b+c)(c+a)</em></h3><h3><em></em></h3><h3><em>2/c+a = 1/b+c + 1/a+b</em></h3><h3><em>1/c+a + 1/c+a = 1/b+c + 1/a+b</em></h3><h3><em>1/c+a - 1/b+c = 1/a+b - 1/c+a</em></h3><h3><em></em></h3><h3><em>2nd term - 1st term = 3rd term - 2nd term
</em></h3><h3><em>Thus 1/b+c, 1/c+a, 1/a+b are in AP.</em></h3><h3><em></em></h3><h3><em>HOPE IT HELPS !!!</em></h3><h3><em>THANK YOU !!!</em></h3>
I think its 7,900 if not then you are correct
Answer:
Step-by-step explanation:
Each signal unit cubes are 1 cm to each side
the dimensions of the large cube is 4 by 6 by 3 width height and depth
a) volume of the cube Vol = area of the base times height
area of the base = the width times the depth
Volume = Base Depth
= Width x Depth x Height
= 4 x 3 x 6
= 12 x 6
Vol = 72 cm ³
b ) the volume of the smaller cuboid has different dimensions
the smaller cube is 2 by 2 by 1 width height and depth
Volume = Base Depth
= Width x Depth x Heigh
= 2 x 2 x 1
Vol smaller cuboid = 4
How many smaller cubes can be made?
The obvious answer might be to straight up divide the large cube volume by the smaler cuboid volume. That might work IF all of the cuboid dimensions divide evenly into the cube dimensions.
Number of cuboid = Volume of the cube / Volume of the cuboid
= 72 / 4
= 18
Check this answer by dividing the dimension of the cube by the cuboid
4 by 6 by 3
2 by 2 by 1
(4/2) by (6/2) by (3/1)
2 by 3 by 3 = 2 x 3 x 3 = 18
The least common denominator (LCM) of these three terms is just the variable a.
Answer: option C, y = 4
Step-by-step explanation:
first, i simplified the equation.
y = ^3sqt64
then, i just calculated that.
y = 4