The solution is the x intercept
In this case the x- intercept is
(3,-2) or B
So you are seeing how much time it'll take so you solve for "t", the time.
<span>So you take the formula A=Pe^(rt) </span>
<span>A=2000 because it's the end value </span>
<span>P=20 because it's the starting value </span>
<span>r=.85 since 85%=.85 and .85 is the rate </span>
<span>Plug the values in and you get 2000=20e^(.85t) </span>
<span>What you do is you divide by 20 so you get 100=e^(.85t) </span>
<span>Take the natural logarithm of both sides 'cause of e and a natural log is written as ln so you get </span>
<span>ln 100=.85t ln e and because you can use the power rule you end up with .85t ln e and </span>
<span>ln e=1 so you have ln 100 = .85t so you divide by .85 so (ln 100)/.85=t and t=5.4178472776331 </span>
<span>hours </span>
<span>3. Exponential decay: </span>
<span>A= Pe^(rt) </span>
<span>where </span>
<span>A is the final amount </span>
<span>P is the initial value </span>
<span>r is rate of decay </span>
<span>t is time (years) </span>
<span>Let's say x is the initial amount then (1/2)x=xe^(32r) </span>
<span>I used x because the value isn't given but anyway division by x would give you 1/2=e^(32r) </span>
<span>Take the ln of both sides so ln 1/2=32r ln e and then ln e=1 so ln 1/2=32r. </span>
<span>Divide both sides by 32 and you'd get (ln 1/2)/32=r and r= -0.021660849392498 </span>
<span>4. Another depreciation question. </span>
<span>Each year the item retains 88% of its last-year value. </span>
<span>Solve: 250,000(0.88)^x = 100,000 </span>
<span>0.88^x = 0.4 </span>
<span>x = [log0.4]/[log0.88] </span>
<span>x = 7.168 years </span>
Slope: (y2-y1)/(x2-x1)
(12-2)/(2-7) = 10/-5 = -2
Y = -2x + b
2 = -2(7) + b, b = 16
Y = -2x + 16
Answer:
The inverse is ((5-x)/4) ^ 1/3
Step-by-step explanation:
y = 5-4x^3
Exchange x and y
x = 5-4y^3
Subtract 5 from each side
x-5 =5-5-4y^3
x-5 = -4y^3
Divide each side by -4
(x-5)/ -4 = y^3
Take the cube root
((x-5)/ -4) ^ 1/3 = y^ 3 ^1/3
((5-x)/4) ^ 1/3 = y
The inverse is ((5-x)/4) ^ 1/3
