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Tju [1.3M]
3 years ago
8

What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41

Mathematics
1 answer:
scZoUnD [109]3 years ago
4 0
The original data set is 
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}

Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70} 
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median. 

The value in the 8th slot is 54, so this is the median

Divide the sorted data set into two lists. I'll call them L and U 
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).

Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value. 

Therefore, Q3 = 62

Answer: 62</span>
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A rectangles length is 2 meters greater than its width if the e perimeter is greater than 112 what is the rectangles possible wi
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Answer:

Step-by-step explanation:

Perimeter of a rectangle = 2(L +W)        

Given L = W + 2      and the perimeter is greater than 112 meters?

  P rect    <   2(L +W)        L = W + 2

  P rect    <   2(W + 2 +W)

                <   2(2W+2)

  112         <     4W + 4        solve for W

(112 - 4)/4  <   (4W +4 - 4)/4              

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Answer:

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Step-by-step explanation:

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2 years ago
Find the derivative of f(x) = 12x^2 + 8x at x = 9.
zvonat [6]

Answer:

224

Step-by-step explanation:

We will need the following rules for derivative:

(f+g)'=f'+g' Sum rule.

(cf)'=cf' Constant multiple rule.

(x^n)'=nx^{n-1} Power rule.

(x)'=1 Slope of y=x is 1.

f(x)=12x^2+8x

f'(x)=(12x^2+8x)'

f'(x)=(12x^2)'+(8x)' by sum rule.

f'(x)=12(x^2)+8(x)' by constant multiple rule.

f'(x)=12(2x)+8(1) by power rule.

f'(x)=24x+8

Now we need to find the derivative function evaluated at x=9.

f'(9)=24(9)+8

f'(9)=216+8

f'(9)=224

In case you wanted to use the formal definition of derivative:

f'(x)=\lim_{h \rightarrow 0} \frac{f(x+h)-f(x)}{h}

Or the formal definition evaluated at x=a:

f'(a)=\lim_{h \rightarrow 0} \frac{f(a+h)-f(a)}{h}

Let's use that a=9.

f'(9)=\lim_{h \rightarrow 0} \frac{f(9+h)-f(9)}{h}

We need to find f(9+h) and f(9):

f(9+h)=12(9+h)^2+8(9+h)

f(9+h)=12(9+h)(9+h)+72+8h

f(9+h)=12(81+18h+h^2)+72+8h

(used foil or the formula  (x+a)(x+a)=x^2+2ax+a^2)

f(9+h)=972+216h+12h^2+72+8h

Combine like terms:

f(9+h)=1044+224h+12h^2

f(9)=12(9)^2+8(9)

f(9)=12(81)+72

f(9)=972+72

f(9)=1044

Ok now back to our definition:

f'(9)=\lim_{h \rightarrow 0} \frac{f(9+h)-f(9)}{h}

f'(9)=\lim_{h \rightarrow 0} \frac{1044+224h+12h^2-1044}{h}

Simplify by doing 1044-1044:

f'(9)=\lim_{h \rightarrow 0} \frac{224h+12h^2}{h}

Each term has a factor of h so divide top and bottom by h:

f'(9)=\lim_{h \rightarrow 0} \frac{224+12h}{1}

f'(9)=\lim_{h \rightarrow 0}(224+12h)

f'(9)=224+12(0)

f'(9)=224+0

f'(9)=224

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Answer:

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Tim needs to save 70 more dollars to buy a computer.

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