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Nat2105 [25]
3 years ago
14

Lines e and f are parallel. The mAngle9 = 80° and mAngle5 = 55°. Parallel lines e and f are cut by transversal c and d. All angl

es are described clockwise, from uppercase left. Where lines e and c intersect, the angles are: 1, 2, 4, 3. Where lines f and c intersect, the angles are 5, 6, 8, 7. Where lines e and d intersect, the angles are 9, 10, 12, 11. Where lines f and d intersect, the angles are 13, 14, 16, 15. Which angle measures are correct? Select three options. mAngle2 = 125° mAngle3 = 55° mAngle8= 55° mAngle12 = 100° mAngle14 = 100°

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
7 0

Answer:

A

C

E

Step-by-step explanation:

brilliants [131]3 years ago
4 0

Answer:

(A)m\angle 2=125^\circ\\(C)m\angle 8=55^\circ\\(E)m\angle 14=100^\circ

Step-by-step explanation:

The diagram of the problem is drawn and attached.

Given that:

m\angle 9 =80^\circ\\m\angle 5 =55^\circ

m\angle 5+ m\angle 6=180^\circ\\55^\circ+ m\angle 6=180^\circ\\m\angle 6=180^\circ-55^\circ\\m\angle 6=125^\circ\\$Now:\\m\angle 6 = m\angle 2 $(Corresponging angles)\\Therefore m\angle 2=125^\circ\\

m\angle 5= m\angle 8=55^\circ $(Vertically Opposite Angles)

Also

m\angle 9+ m\angle 10=180^\circ\\80^\circ+ m\angle 10=180^\circ\\m\angle 10=180^\circ-80^\circ\\m\angle 10=100^\circ\\$Now:\\m\angle 10 = m\angle 14 $(Corresponging angles)\\Therefore m\angle 14=100^\circ\\

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Answer:

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Step-by-step explanation:

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4 0
3 years ago
For what value(s) of k will the relation not be a function
skelet666 [1.2K]

We are given two relations

(a)

Relation (R)

R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

k-8.3+2.4k=-\frac{3}{4} k

3.4k-8.3=-\frac{3}{4}k

3.4k\cdot \:10-8.3\cdot \:10=-\frac{3}{4}k\cdot \:10

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(b)

S = {(2−|k+1| , 4), (−6, 7)}

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any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

2-|k+1|=-6

2-\left|k+1\right|-2=-6-2

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Since, this is absolute function

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|f\left(k\right)|=a\quad \Rightarrow \:f\left(k\right)=-a\quad \mathrm{or}\quad \:f\left(k\right)=a

k+1=-8\quad \quad \mathrm{or}\quad \:\quad \:k+1=8

we get

k+1=-8\quad

k=-9

k+1=8\quad

k=7

so,

k=-9\quad \mathrm{or}\quad \:k=7...............Answer

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