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Brrunno [24]
2 years ago
14

Explain the similarities between these ratios

Mathematics
2 answers:
EastWind [94]2 years ago
8 0

3. times of 4

I don’t know if 5 is supposed to be 35/42 but if it’s 36/42 I don’t know

aksik [14]2 years ago
4 0
3. Múltiple of 4
I don’t know if 5 is supposed to be 35/42 but if it’s 36/42 I don’t know
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64/100 is easy its just 64 out of 100
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3 years ago
Find the quotient of 675 and 5
Stells [14]
The quotient of 675 and 5 would be 135.
675/5=135
Hope this helps!
8 0
2 years ago
A number x increased by 17 is 106
Lorico [155]

Answer:

x = 89

Step-by-step explanation:

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6 0
2 years ago
A data set includes 103 body temperatures of healthy adult humans having a mean of 98.3degreesF and a standard deviation of 0.73
faust18 [17]

Answer:

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher

Step-by-step explanation:

Data provided in the question:

sample size, n = 103

Mean temperature, μ = 98.3

°

Standard deviation, σ = 0.73

Degrees of freedom, df = n - 1 = 102

Now,

For Confidence level of 99%, and df = 102, the t-value = 2.62      [from the standard t table]

Therefore,

CI = (Mean - \frac{t\times\sigma}{\sqrt{n}},Mean + \frac{t\times\sigma}{\sqrt{n}})

Thus,

Lower limit of CI =  (Mean - \frac{t\times\sigma}{\sqrt{n}})

or

Lower limit of CI =  (98.3 - \frac{2.62\times0.73}{\sqrt{103}})

or

Lower limit of CI = 98.11

and,

Upper limit of CI =  (Mean + \frac{t\times\sigma}{\sqrt{n}})

or

Upper limit of CI =  (98.3 + \frac{2.62\times0.73}{\sqrt{103}})

or

Upper limit of CI = 98.49

Hence,

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher and  the mean temperature could very possibly be 98.6°F

7 0
3 years ago
Which is larger, 7 x 10-8or 3 x 10-9? Estimate how many times larger.
olasank [31]
7 x 10 - 8 is larger by approximately 30
4 0
3 years ago
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