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2 years ago

1.In a class of 45 pupils ,21play chess and 23 play cards and 5play both games

Mathematics

1 answer:

Mumz [18]2 years ago

8 0

Step-by-step explanation:

(a)

ii.

21 - 5 = 16 play only chess.

iii.

23 - 5 = 18 play only cards

5 play both.

that is 16+18+5 = 39 that play at least one of these games.

so, 45 - 39 = 6 don't play any of these games.

(b)

we have 16+18 = 34 pupils out of 45 that play exactly one game.

so the probabilty to pick one of them is as usual

desired cases / total cases = 34/45 =

= 0.755555555... ≈ 0.76

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Answer:

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Step-by-step explanation:

we have

$3y=4x-6$

isolate the variable y

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simplify

$y=\frac{4}{3}x-2$ -----> equation A

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Isolate the variable y

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Divide by 6 both sides

$y=\frac{8}{6}x-\frac{30}{6}$

simplify

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Compare equation A and equation B

The slopes are the same and the y-intercepts are different

Remember that

If two lines has the same slope, then the lines are parallel

therefore

In this problem line A and line B are parallel lines

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2 years ago

Dylan invested $20,000 in an account paying an interest rate of 5.3% compounded continuously. Assuming no deposits or withdrawal

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2 years ago

How many ml of a 20% acid mixture and a 80% acid mixture should be mixed to get 120ml of a 35% acid mixture?

shutvik [7]

Answer:

Volume of Mixture A =90 ml

Volume of Mixture B =30 ml

Step-by-step explanation:

Let say, Mixture A + Mixture B = Mixture C

Volume of Mixture A is x

Volume of Mixture B is y

So, Volume of Mixture C is x+y = 120 ml

Now, Acid contain in Mixture A is 20% =0.2x

Acid contain in Mixture B is 80% =0.8y

Also, Acid contain in Mixture C is 35% =(0.35)(x+y) = 0.35×120=42

Now, we know that,

Acid contain of Mixture A + Acid contain of Mixture B=Acid contain of Mixture C

∴ 0.2x+0.8y=42

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2x+8y=420 and x+y = 120

Solving above equation...

∴ x=120-y

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∴ 240-2y+8y=420

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Replacing y value in any equation

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3 years ago

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Naddik [55]

Answer:

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2 years ago

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