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hram777 [196]
2 years ago
12

Higher Order Functions used for simulations of dice rolls. Definition: An n-sided dice function takes no arguments and always re

turns an int from 1 to n, inclusive. Types of n-sided dice functions: - Randomized: a randomized dice function can be fair, meaning that ir produce each possible outcome from 1 to n with equal probability. Examples: four_sided, six_sided - Deterministic: a deterministic dice function will be used for testing. Deterministic test dice functions always cycle through a fixed sequence of n values. - We write a make_fair_dice higher-order function to return a fair, randomized n-sided dice function. - We write a make_test_dice higher-order function that will return a deterministic, testing n-sided dice function.
Computers and Technology
1 answer:
tiny-mole [99]2 years ago
5 0

Answer:

#include <iostream>

#include <time.h>

#include <string>

using namespace std;

int main(){

srand(time(NULL));

cout<<"Throw dice"<<endl;

int b =0;

int a=0;

a=rand()%6;

b=rand()%6;

for (int i =0;i<1;i++)

{cout<<"dice one: "<<a<<endl;}

for (int i =0;i<1;i++)

{cout<<"dice two: "<<b<<endl;}

if(a>b)

{cout<<"first dice won"<<endl;}

if(b>a)

{cout<<"second dice won"<<endl;}

else{cout<<"they are same"<<endl;

return main();

}

return 0;

}

Explanation:

/*best dice roll game just for you change it as you want but all necessary things are there/*

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Create the following SQL Server queries that access the Northwind database. Place them in a zip file and place the zip file in t
neonofarm [45]

Answer:

1. SELECT e.EmployeeID, e.FirstName, e.LastName, COUNT(*) as OrderByEmployee FROM Employees e

JOIN Orders o

ON e.EmployeeID = o.EmployeeID

WHERE YEAR(o.OrderDate) = '1996'

GROUP BY e.EmployeeID,e.FirstName,e.LastName

ORDER BY OrderByEmployee DESC

2. SELECT o.OrderID,c.CustomerID, o.OrderDate,SUM((od.Quantity)*

od.UnitPrice - od.Discount)) as TotalCost FROM Orders o

JOIN [Order Details] od

ON od.OrderID = o.OrderID

JOIN Customers c

ON o.CustomerID = c.CustomerID

WHERE (MONTH(OrderDate)= 7 OR MONTH(OrderDate) = 8) and

YEAR(OrderDate) = 1996

GROUP BY o.OrderID,c.CustomerID, o.OrderDate

ORDER BY TotalCost DESC

3. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c

JOIN Orders o

ON o.CustomerID = c.CustomerID

JOIN [Order Details] od

ON od.OrderID = o.OrderID

WHERE c.Country = 'USA'

GROUP BY c.CustomerID, c.CompanyName, c.City

ORDER BY c.City, c.CustomerID

4. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c

JOIN Orders o

ON o.CustomerID = c.CustomerID

JOIN [Order Details] od

ON od.OrderID = o.OrderID

WHERE c.Country = 'USA'

GROUP BY c.CustomerID, c.CompanyName, c.City

HAVING COUNT(o.OrderID) > 3

ORDER BY c.City, c.CustomerID

5. SELECT p.ProductID, p.ProductName, s.ContactName as SupplierName, MAX(o.OrderDate) as LastOrderDateOfProduct FROM Products p

JOIN Categories c

ON c.CategoryID = p.CategoryID

JOIN Suppliers s

ON s.SupplierID = p.SupplierID

JOIN [Order Details] od

ON od.ProductID = p.ProductID

JOIN Orders o

ON o.OrderID = od.OrderID

where c.CategoryName = 'Grains/Cereals'

GROUP BY p.ProductID, p.ProductName, s.ContactName

ORDER BY SupplierName, p.ProductName

6. SELECT p.ProductID, p.ProductName, Count(DISTINCT c.CustomerID ) as OrderByThisManyDistinctCustomer

FROM Products p

JOIN [Order Details] od

ON od.ProductID = p.ProductID

JOIN Orders o

ON o.OrderID = od.OrderID

JOIN Customers c

ON c.CustomerID = o.CustomerID

where YEAR(o.OrderDate) = 1996

GROUP BY p.ProductID, p.ProductName

Explanation:

The six query statements returns data from the SQL server Northwind database. Note that all the return data are grouped together, this is done with the 'GROUP BY' Sql clause.

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