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NeTakaya
3 years ago
12

An artist drew a rectangle. the artist then modified the rectangle so thatthe length ofthe rectawngle increased by 30 percent an

d the width of the rectangle decreased by 40 percent. after the modification, what was the percent decrease in the area of the rectangle?
Mathematics
1 answer:
VLD [36.1K]3 years ago
7 0
The dimensions of the original rectangle 
length - L
width - W
area = L*W = LW
after the modification, new dimensions are
length increased by 30 % 
Length = L * 1.3 = 1.3L
Width = W * 0.6 = 0.6W
new area = 1.3L * 0.6W
                = 0.78LW
the percent decrease in area 
decrease % = (difference in area)/original area * 100
                    = (LW - 0.78LW)/LW * 100
                    = 0.22LW/LW * 100
                    = 22%
percent decrease is 22%
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