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NeTakaya
2 years ago
12

An artist drew a rectangle. the artist then modified the rectangle so thatthe length ofthe rectawngle increased by 30 percent an

d the width of the rectangle decreased by 40 percent. after the modification, what was the percent decrease in the area of the rectangle?
Mathematics
1 answer:
VLD [36.1K]2 years ago
7 0
The dimensions of the original rectangle 
length - L
width - W
area = L*W = LW
after the modification, new dimensions are
length increased by 30 % 
Length = L * 1.3 = 1.3L
Width = W * 0.6 = 0.6W
new area = 1.3L * 0.6W
                = 0.78LW
the percent decrease in area 
decrease % = (difference in area)/original area * 100
                    = (LW - 0.78LW)/LW * 100
                    = 0.22LW/LW * 100
                    = 22%
percent decrease is 22%
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STALIN [3.7K]

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Given that the graph of the quadratic function.

We need to determine the value of a in the function's equation.

<u>Value of a:</u>

The value of a can be determined using the formula,

y=a(x-h)^2+k

where (h,k) is the vertex and a is a constant.

From the graph, it is obvious, that the vertex of the parabola is (0,9).

Thus, substituting the vertex (h,k) = (0,9) in the above formula, we get;

y=a(x-0)^2+9

y=ax^2+9  -------- (1)

Let us substitute any one of the coordinate that the graph passes through to determine the value of a.

Let us substitute the point (3,0) in the equation (1), we have;

  0=a(3)^2+9

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Thus, the value of a is -1.

Hence, Option B is the correct answer.

3 0
2 years ago
How many liters each of a 45% acid solution and a 70% acid solution must be used to produce 50 liters of a 65% acid solution? (R
puteri [66]

Answer:

The number of liters of the 45% acid solution = 10 liters

The number of liters of the 70% acid solution is = 40 liters

Step-by-step explanation:

How many liters each of a 45% acid solution and a 70% acid solution must be used to produce 50 liters of a 65% acid solution? (Round to two decimal places if necessary.)

Let x be the number of liters of the 45% acid solution

The number of liters of the 70% acid solution is y

x + y = 50

x = 50 - y

Also

How many liters each of a 45% acid solution and a 70% acid solution must be used to produce 50 liters of a 65% acid solution?

We have:

45% × x + 70% × y = 65% × 50

0.45x + 0.70y = 0.65 × 50

0.45x + 0.70y = 32.5

We substitute x = 50 - y in the equation

0.45(50 - y) + 0.70y = 32.5

= 22.5 - 0.45y + 0.70y = 32.5

= - 0.45y + 0.70y = 32.5 - 22.5

= 0.25y = 10

Divide both sides by 0.25

= y = 10/0.25

y = 40 liters

x = 50 - y

x = 50 - 40

x = 10 liters

Hence,

The number of liters of the 45% acid solution = 10 liters

The number of liters of the 70% acid solution is = 40 liters

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2 years ago
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4 0
2 years ago
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Dominik [7]

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3 years ago
2(x+16)= 6x please help me :)
jeka94

Let solve:

  2(x+16) = 6x\\2x + 32 = 6x\\32 = 4x\\4x = 32\\x = 8

Thus <u>x = 8</u>

<u></u>

Hope that helps!

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2 years ago
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