Given:
Desmond deposits $ 50 monthly.
Yearly he deposits = $50×12 = $ 600
Rate of interest compounded monthly = 4.7%
To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.
Formula
where,
A be the final amount
P be the principal
r be the rate of interest
t be the time and
n be the number of times the interest is compounded.
Now,
Taking,
P = 600, r = 4.7, n = 12, t = 10 we get,
or, 
or, 
Now,
At starting he has $ 600
At the end of 10 years he will be having $ 959.1
So,
The amount of change in his account = $ (959.1-600) = $ 359.1
Therefore the rate of change = 
= 59.85%
Hence,
a) His account will contain $ 959.1 after 10 years.
b) The rate of change in his account is 59.85% after 10 years.
Answer:
y = 3x + 5
Step-by-step explanation:
Two lines which are parallel have the same gradient. This means that the parallel line must have a gradient of 3x
y = 3x + c
To figure out c you substitute in the given coordinate for the x and y values
8 = 3(1) + c
c = 5
y = 3x + 5
Answer:
4(9a^4+4y^2)
Step-by-step explanation:
factor out common term
I agree with him that’s the answer
<em>IMPORTANT THIGNS TO REMEMBER:</em>
- Has 20 lb. dog food!
- Gives dog 1 3/5 everyday!
- Find how much eaten after 2 days!
- Find how much is left!
<em>ANSWER:</em>
Dog has eaten 3 1/5 after 2 days!
There is 16 4/5 left in bag!
<em>EXPLANATION:</em>
Since she gives 1 3/5 to her dog everyday and their asking for 2 days you would multiply 1 3/5 × 2 OR add 1 3/5 + 1 3/5
Which would give you 3 1/5
So, the dog has eaten 3 1/5 lb. of dog food in 2 days.
However then, you would subtract 20 lb. - 3 1/5 lb. because there is 20 lb. dog food in all and the dog has eaten 3 1/5 of it. This would give you 16 4/5 lb.
Meaning there is 16 4/5 lb. left in the bag of dog food!
