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a_sh-v [17]
2 years ago
15

Find the surface area of the net ILL MARK AS BRAILIEST

Mathematics
1 answer:
adell [148]2 years ago
5 0

Answer:

200

Step-by-step explanation:

Surface are of cube = 6a^2

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1. Chris takes 25 minutes to replace one car tyre.
vekshin1

Chris and Jim must replace a <em>total</em> quantity of 17 tyres.

<h3>What is the minimum number of tyres to be replaced?</h3>

In this problem we must use an inequality of the form f(x) ≥ a, where f(x) is the difference between the number of tyres replaced by Jim and the number of tyres replaced by Chris:

(25/20) · x - x ≥ 3

(5/20) · x ≥ 3

x ≥ 12

Then, the <em>minimum</em> number of tyres to be replaced is n = 15 + 12 = 17 tyres.  

To learn more on inequalities: brainly.com/question/20383699

#SPJ1

3 0
1 year ago
Is there a rational number between 1/7 and 1/8
telo118 [61]
1/7 = 2/14 =  <span> <span> <span> 0.1428571429 </span> </span> </span>
1/8 = 2/16 =  0.125
2/15 = <span> <span> <span> 0.1333333333 </span> </span> </span>
So, 2/15 is between 1/7 and 1/8
(and there are an infinite amount of numbers between 1/7 and 1/8)


5 0
3 years ago
Using the side lengths, 20, 15 , 15 , determine whether the triangle is acute, obtuse, or right
Ymorist [56]

acute, hope this helps

8 0
3 years ago
Read 2 more answers
Given a mean of 52.3 and a standard deviation of 1.8, what is the z-score of the value 51.8 rounded to the nearest tenth?
postnew [5]
The z-score of a certain data point in the given statistical data is calculated through the equation,
                                           z-score = (x - m) / sd
where x is the data point, m is the mean and sd is the standard deviation. 
Substituting the known values,
                                           z-score = (51.8 - 52.3) / 1.8
                                           z-score = -0.277
Rounding the answer to the nearest tenth will give an answer of -0.3. 
8 0
3 years ago
9. Which sentence explains the relationship between two concepts?
Sholpan [36]

Answer:

I hope it'll help you...

5 0
2 years ago
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