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Afina-wow [57]
2 years ago
13

A seed company planted a floral mosaic of a national flag. the perimeter of the rectangular planting area is 420 feet. the lengt

h of the area is 110 feet longer than the width.
a.) write a system of equations to relate the length and width of the planting area

b.) use the system of equations to determine the length and width of the planting area
Mathematics
1 answer:
pantera1 [17]2 years ago
3 0

Answer:

Length = 50 feet

Width = 160 feet

Explanation:

I'm assuming the flagpole is not included in this question.

w

=

w

i

d

t

h

l

=

≤

n

>

h

The length compared to the width is:

w

=

l

+

110

<-- equation 1

The formula for perimeter:

P

=

2

w

+

2

l

420

=

2

w

+

2

l

<-- equation 2

Sub the first equation into the second.

420

=

2

(

l

+

110

)

+

2

l

Now you can solve for

l

algebraically.

420

=

2

l

+

220

+

2

l

4

l

=

200

l

=

50

Sub the found length into the first equation to find the length.

w

=

(

50

)

+

110

w

=

160

Therefore the flag is 50 feet long and 160 feet wide.

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The length of a rectangle is increasing at a rate of 4 meters per day and the width is increasing at a rate of 1 meter per day.
puteri [66]

Answer:

\displaystyle \frac{dA}{dt} = 102 \ m^2/day

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Geometry</u>

Area of a Rectangle: A = lw

  • l is length
  • w is width

<u>Calculus</u>

Derivatives

Derivative Notation

Implicit Differentiation

Differentiation with respect to time

Derivative Rule [Product Rule]:                                                                              \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle l = 10 \ meters<u />

<u />\displaystyle \frac{dl}{dt} = 4 \ m/day<u />

<u />\displaystyle w = 23 \ meters<u />

<u />\displaystyle \frac{dw}{dt} = 1 \ m/day<u />

<u />

<u>Step 2: Differentiate</u>

  1. [Area of Rectangle] Product Rule:                                                                 \displaystyle \frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}

<u>Step 3: Solve</u>

  1. [Rate] Substitute in variables [Derivative]:                                                    \displaystyle \frac{dA}{dt} = (10 \ m)(1 \ m/day) + (23 \ m)(4 \ m/day)
  2. [Rate] Multiply:                                                                                                \displaystyle \frac{dA}{dt} = 10 \ m^2/day + 92 \ m^2/day
  3. [Rate] Add:                                                                                                      \displaystyle \frac{dA}{dt} = 102 \ m^2/day

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

Book: College Calculus 10e

8 0
3 years ago
E x e x e x e x f divided by e x e x e x f x f
meriva

Answer:

thx for points

Step-by-step explanation:

6 0
3 years ago
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How can I solve this Inequality ?
musickatia [10]
Add 12 to both sides. 

q-12 > 3
q > 15

ANSWER: q > 15
4 0
3 years ago
A trimming operation at a local manufacturer produces rods whose length conforms to unifrom distribution with a minimum of 18cm
MariettaO [177]

Answer:

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

Step-by-step explanation:

Given: uniform distribution with min and max values of 18 and 33 respectively.

To find : probability density for upper cumulative frequency i.e 25.8 at least means x\geq25.8  upto 33 cm i.e the maximum limit of function.

Solution:

we have by definition , of uniform distribution

we get , probability density function defines as :

<em>F(x,a,b)= </em>\frac{1}{b-a}<em>   </em>a\leq x\leq b

            =1/(33-18)=1/15=0.0667.

this is probability density function.

here the x=25.8 , a=18 and b=33

for lower cumulative frequency it defines as ;

P(x,a,b)=\frac{x-a}{b-a} =25.8-18/33-18=0.52

for upper cumulative frequency it defines as ;

Q(x,a,b)=b-x/b-a=33-25.8/33-18=0.48

here at least 25.8 cm probability means it should be greater than a value(18cm) hence it is provided by the upper cumulative frequency

i.e. Q(x,a,b)=0.48

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

7 0
3 years ago
Find the equation of the line passing through the point (8, -4) and slope -4.
ehidna [41]

Answer:

y+4x=36

Step-by-step explanation:

the answer isn't in the choice

3 0
3 years ago
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