After she worked out the problem, she had a discrepancy (disagreement) of
about 45% between her estimate and the quotient.
That's a lot ! There's almost definitely a major mistake somewhere, and
there really isn't any way to tell whether the mistake is in the estimate or
in the quotient.
My answer to the question is that Lilly has to go all the way back to the
beginning, and do the whole thing again. Only this time, she has a harder
job to do: She not only has to make another estimate and work out the
division problem again. This time, she also has to find the mistake that
she made the first time ... and there may be more than one of them.
My answer is should: increase of 4.5
......................
P.S..If you have options then it's better................
Answer: 
Step-by-step explanation:
Given: A cubic kilometer=
cubic centimeters
The volume of world’s oceans=
cubic kilometers of water.
⇒ The volume of world’s oceans=
cubic centimeters of water.
Volume of a bucket = 20,000 cubic centimeters of water.
The number of bucket-loads would it take to bucket out the world’s oceans
![\Rightarrow\ n=\frac{1.4\times10^{9+15}}{0.2\times10^5}......[a^n\times a^m=a^{m+n}]\\\Rightarrow\ n=7\times10^{24-5}.....[\frac{a^m}{a^n}=a^{m-n}]\\\Rightyarrow\ n=7\times10^{19}](https://tex.z-dn.net/?f=%5CRightarrow%5C%20n%3D%5Cfrac%7B1.4%5Ctimes10%5E%7B9%2B15%7D%7D%7B0.2%5Ctimes10%5E5%7D......%5Ba%5En%5Ctimes%20a%5Em%3Da%5E%7Bm%2Bn%7D%5D%5C%5C%5CRightarrow%5C%20n%3D7%5Ctimes10%5E%7B24-5%7D.....%5B%5Cfrac%7Ba%5Em%7D%7Ba%5En%7D%3Da%5E%7Bm-n%7D%5D%5C%5C%5CRightyarrow%5C%20n%3D7%5Ctimes10%5E%7B19%7D)
hence, 
bucketloads would it take to bucket out the world’s oceans.
Answer:
1/12
Step-by-step explanation:
The whole circumference (i.e complete circle) is an arc which measures 360°
in our case, it is given that our arc measures only 30°
the fraction of our arc of 30° to the complete circle of 360° is
30/360
= 3/36
= 1/12
