Given data:
The given distance is d=26 km.
We know 1 kilometer is equal to approx 0.621 miles.
1km= 0.621 miles
Multiply the above expression with 26 on both sides.
26(1 km)= 26(0.621 miles)
26 km= 16.146 miles.
Thus, 26 kilometer is equal to 16.146 miles
Area of right-angled triangle is given by;
Area, A = 1/2 *b*h, Where b=base, h=height
Therefore,
A1 = 1/2bh = 16 in^2
A2 = 1/2 (2b)(2h) = 2bh
Ratio of increase = A2/A1 = {2bh}/(1/2bh} = 4 (the area is increased 4 times)
The,
A2 = 4*16 = 64 in^2
Therefore,
The area is increased by (64-16) = 48 in^2
Answer:
C
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is
Here [ a, b ] = [ - 10, 10 ], thus
f(b) = f(10) = 10² + 9(10) + 18 = 100 + 90 + 18 = 208
f(a) = f(- 10) = (- 10)² + 9(- 10) + 18 = 100 - 90 + 18 = 28, thus
average rate of change = 
= 
= 9
I hope this helps you
Volume=4/3.pi.r^2.h
Volume =4/3.3,14.5^2.3
Volume =314
Answer:
cos theta = 4/5
Step-by-step explanation:
Since this is a right triangle
Cos theta = opp side/ hypotenuse
Cos theta = 8/10
cos theta = 4/5
