1. 10x
2. 18g
3. 6m
4. 4p
5. -5y
6. 9w
7. c^2+3d
8. 3a^2+2b^2+6a
9. 3x^2+x
10. 16x-y+3
11. 68x^2-34x-1
12. 32
13. 32
14. -9
15. 3m+3n
16. 6x-6y
17. 15f+5
Answer : 29.5°
Given r = 10, q = 20, and Q = 100°
From the attached figure we can see that two sides and one angle is given
We use sine rule to find angle R

In triangle QRS

r = 10, q = 20, and Q = 100°

Replace all the values


=sin R
0.4932403876 = sin (R)
R= 
R= 29.5 degrees