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wariber [46]
2 years ago
6

HELP PLEASE SHOW STEPS I HAVE NO IDEA WHAT TO DO. I HAVE BEEN TRYING TO FIGURE IT OUT BUT I CAN’T.

Mathematics
2 answers:
weqwewe [10]2 years ago
8 0

Answer: x^{2} +23x+49

Step-by-step explanation:

To find the area of the shaded region, you must find the area of the larger rectangle [(x+10)×(2x+5)] and subtract the area of the smaller rectangle [(x+1)×(x+1)] from it.

First, you simplify the larger rectangle's area:

(x+10)×(2x+5) = 2x^{2} +25x+50

Then, simplify the smaller rectangle's area:

(x+1)×(x+1) = x^{2} +2x+1

Finally, subtract the smaller rectangle's area from the larger rectangle's area:

(2x^{2} +25x+50) - (x^{2} +2x+1) = x^{2} +23x+49

Therefore, the final answer is x^{2} +23x+49.

I hope this helps!

Svetlanka [38]2 years ago
7 0

\text{Area of rectangle}=\text{lengh}\times\text{width}\\\text{Area of square}=\text{side}^2

You just need to find differens between rectangle and square

\text{lengh}\times\text{width}-\text{side}^2\\\\(x+10)(2x+5)-(x+1)^2=2x^2+5x+20x+50-x^2-2x-1=x^2+23x+49

x^2+23x+49\:\text{is our answer}

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Answer:

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Step-by-step explanation:

1. Using the point of intersections, we use the substitution method to find the coordinates of the line parallel to 2x-y-9=0

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y= -4-5x

substituting the value of y in 2x+3y=1:

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substituting x=-1 in y= -4-5x:

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(x,y)= (-1,1)

2. Using y=mx+c and making y the subject of the formula 2x-y-9=0 and using the coordinate we found earlier, we will find the equation of the parallel line. (We make y the subject of the formula to find the gradient)

2x-y-9=0\\2x-9=y\\y= 2x-9

y= mx+c\\

-1= 2 x 1 +c

-3=c

  • y= 2x-3

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