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2 years ago

Graphing Piecewise Functions

Mathematics

1 answer:

netineya [11]2 years ago

7 0

I believe the answer to your graphing piecewise function is the 2nd picture

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The rabbit population in a certain area is 500% of last year's population. There are 700 rabbits this year. How many were the

Ksenya-84 [330]

For this case we have the following data:

700 rabbits that represent 500% of the population of last year. So, to obtain the rabbit population of last year, we developed a rule of three:

700 -----------> 500%

x ---------------> 100%

Where x represents the rabbit population of last year.

Clearing x we have:

$x = \frac{ 100 * 700}{500}$

$x = 140$ rabbits

In this way, last year there was a population of 140 rabbits.

Answer:

140 rabbits

8 0

3 years ago

A square has side length represented by X +4 inches write an expression to represent the area. Express your answer as a trinomia

romanna [79]

Answer:

$A=(x^2+16+8x)\ \text{inches}^2$

Step-by-step explanation:

Given that,

The side length of a square, l = (x+4) inches

We need to find an expression to represent the area of the square.

The area of a square is given by :

$A=\text{side}^2$

So,

$A=(x+4)^2\\\\A=(x^2+16+8x)\ \text{inches}^2$

So, the area of the square is $(x^2+16+8x)\ \text{inches}^2$ .

7 0

2 years ago

Which correctly lists the three processes that are affected by freeze and thaw cycles? creep, landslide, and deposition depositi

svetlana [45]

Answer:

slump, weathering, and creep

Step-by-step explanation:

edge2020

Freezing and thawing cycle in geology is the process in which water gets in between soil space or rock cracks, freeze in a cold season, and then melt in a warmer season, exerting a force on the soil or rock around it. This force is due to the expansion and contraction of water when it changes from ice to liquid water.

The three geological processes slump, weathering and creep all depend on thawing and freezing cycle among other factors.

Slump: Slump is a type of geological process that occurs when coherent mass of loosely consolidated materials or a rock layer moves a short distance down a slope. The movement of a slump is characterized by sliding along a concave-upward or planar surface. Causes includes earthquake shocks, thorough wetting, freezing and thawing, undercutting, and loading of a slope.

Weathering: This is a geological process that results in the gradual disintegration of rocks into smaller sizes. It is one of the most important soil formation process, and is different from erosion by the degree of movement of the soil formed. Weathering does not move the soil from its origin. Thawing and freezing cycle plays a major role in weathering by helping crack up the rocks and by also tearing the rock apart. plays a major role.

Creep: This is the slow, often imperceptible downslope movement of soil or other debris. The effects of creep is often seen in the presence of physical characteristics like bent trees, tilted fences, and cracked walls. Creep is caused by multiple factors, of which heaving is likely the most important process. Heaving involves the expansion and contraction of rock fragments, and occurs during cycles of wetting and drying, as well as freezing and thawing.

4 0

3 years ago

Read 2 more answers

What is the exact value of sin(theta + beta)?

NISA [10]

Answer: $\frac{-3\sqrt{13}+4\sqrt{3}}{20}$

This is the single fraction of -3*sqrt(13)+4*sqrt(3) up top all over 20.

sqrt = square root

=======================================================

Explanation:

Angle theta is between pi and 3pi/2. This places the angle in quadrant Q3 where both cosine and sine are negative

Use the pythagorean trig identity to get the following:

$\sin^2 \theta + \cos^2 \theta = 1\\\\\sin^2 \theta + \left(-\frac{\sqrt{3}}{4}\right)^2 = 1\\\\\sin^2 \theta + \frac{3}{16} = 1\\\\\sin^2 \theta = 1 - \frac{3}{16}\\\\\sin^2 \theta = \frac{16}{16} - \frac{3}{16}\\\\\sin^2 \theta = \frac{16-3}{16}\\\\\sin^2 \theta = \frac{13}{16}\\\\\sin \theta = -\sqrt{\frac{13}{16}} \ \text{ ... sine is negative in Q3}\\\\\sin \theta = -\frac{\sqrt{13}}{\sqrt{16}}\\\\\sin \theta = -\frac{\sqrt{13}}{4}\\\\$

Angle beta is in Q1 where sine and cosine are positive.

Draw a right triangle with legs 3 and 4. The hypotenuse is 5 through the pythagorean theorem. In other words, we have a 3-4-5 right triangle.

Since $\tan \beta = \frac{3}{4}$ , this means $\sin \beta = \frac{3}{5} \ \text{ and } \ \cos \beta = \frac{4}{5}$

Use these ideas:

sin = opposite/hypotenuse
cos = adjacent/hypotenuse
tan = opposite/adjacent

In this case we have: opposite = 3, adjacent = 4, hypotenuse = 5.

-------------------------------------

To recap:

$\cos \theta = -\frac{\sqrt{3}}{4}\\\\\sin \theta = -\frac{\sqrt{13}}{4}\\\\\cos \beta = \frac{3}{5}\\\\\sin \beta = \frac{4}{5}\\\\$

They lead to this

$\sin\left(\theta + \beta\right) = \sin \theta * \cos \beta - \cos \theta * \sin \beta\\\\\sin\left(\theta + \beta\right) = -\frac{\sqrt{13}}{4} * \frac{3}{5} - \left(-\frac{\sqrt{3}}{4}\right) * \frac{4}{5}\\\\\sin\left(\theta + \beta\right) = -\frac{3\sqrt{13}}{20}+\frac{4\sqrt{3}}{20}\\\\\sin\left(\theta + \beta\right) = \frac{-3\sqrt{13}+4\sqrt{3}}{20}\\\\$

6 0

2 years ago

Can you guys help..please

sergij07 [2.7K]

Answer:

Step-by-step explanation:

IV does not represent y as the function of x since the ordinates share the same abscissa. As we can see in the graph {(4,-1),(4,4),(-4,-1),(-4,4)}

Mark me as brainliest char

5 0

2 years ago