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Nookie1986 [14]
3 years ago
6

The formula for the area of a rhombus is A = a equals StartFraction one-half EndFraction d 1 d 2.D1d2, where d1 and d2 are the l

engths of the diagonals Which are equivalent equations? Select two correct answers.
Mathematics
1 answer:
Gelneren [198K]3 years ago
7 0

Answer:

d1=2A/d2

d2=2A/d1

Step-by-step explanation:

The options of this question are:

1. d₁=2Ad₂

2. d₁= 2A/d₂

3. d₂= d₁/2A

4. d₁= 2A/d₂

5. d₂= 2Ad₁

Given:

A=1/2(d1*d2)

Multiply both sides by 2

We have,

2A=d1*d2

Divide both sides by d2

2A/d2=d1*d2/d2

2A/d2=d1

Therefore, d1=2A/d2

Similarly, from the previous equation

2A=d1*d2

Divide both sides by d1

2A/d1=d1*d2/d1

2A/d1=d2

Therefore,

d2=2A/d1

Options

2. d₁= 2A/d₂

4. d₁= 2A/d₂

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Answer:

5.

Objective C

125x + 200 \geqslant 1200 \\ 125x  \geqslant  1000 \\ x  \geqslant 8

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diamong [38]

Answer:

The answer to your question is:

Step-by-step explanation:

Data

f(x) = -2x² + 8x - 2

Process

                -2x² + 8x = y + 2

                -2(x² - 4x + 4) = y + 2 - 8

                -2(x - 2)² = y - 6

                    (x - 2)² = 1/2 (y - 6)

Vertex = (2, 6)

Axis of symmetry =   x = 2

y-intercept

                 f(0) = -2(0)² + 8(0) - 2

                 f(0) = 0 + 0 - 2

                 f(0) = -2

Domain    (-∞, ∞)

Range    (-∞, 6]

See the graph below

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