Option D should be your answer.
No combo of any of those angles add up to exactly 180 to suggest that they are parallel lines.
Answer:
Look below.
Step-by-step explanation:
Q1. Impossible goes with probability = 0
Unlikely goes with probability < 1/2
Likely goes with probability > 1/2
Certain goes with probability = 1
Q2. So there are 25 aprons in all. Without green there are 18
18 / 25
Q3. Yes, because the everyone gets a fair chance in being picked first since there are 18 kids and 18 slips.
Q4. Number 2 is true
Number 3 is true
Number 5 is true
Q5. There is a probability of 0 because there is only the number 1 - 12 on the die. No greater.
For the first one is definitely 0.12
The second one I was having trouble with, but I know it is not .25 or .75. Looking at the leftover answers I would say .36 because I already used .12. Also .52 and .25 are the givens.
Answer:
a) 6 gigabytes
b) $100
Step-by-step explanation:
Let c represent the total cost in dollars and d represent the amount of data used in gigabytes.
For the first smartphone
One smartphone plan costs $52 per month for talk and messaging and $8 per gigabyte of data used each month.
Equation =
c = 52 + 8d
For the Second smartphone
A second smartphone plan costs $82 per month for talk and messaging and $3 per gigabyte of data used each month.
Equation =>
c = 82 + 3d
How many gigabytes would have to be used for the plans to cost the same?
We would equate both cost to each other
52 + 8d = 82 + 3d
Collect like terms
8d - 3d = 82 - 52
5d = 30
d = 30/5
d = 6
Therefore,
a) The number of gigabytes for the cost of both Smartphone data plans to be the same = 6 gigabytes.
b) The cost of both plans if 6 gigabytes is used =>
c = 52 + 8d
c = 52 + 8 × 6
c = $100
So, Graph of Image 1 is correct.
Step-by-step explanation:
We need to find the graph of the solution o the equation 
Solving:
Adding -3 on both sides
Applying absolute rule: if |u|>a then u>a or u<-a
So, all values greater than 2 and less than -2 are included.
So, Graph of Image 1 is correct.
Keywords: Solving inequalities
Learn more about Solving inequalities at:
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