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KiRa [710]
2 years ago
15

How can you represent a proportional relationship with an equation? PLS help me with an explanation.

Mathematics
2 answers:
earnstyle [38]2 years ago
8 0

Answer:

A proportional relationship between a quantity y and a quantity x that has a constant of proportionality k is represented by the equation y = kx.

Step-by-step explanation:

hope this explains well, good luck !

qwelly [4]2 years ago
4 0
Help me please I am so me if this is wrong I am so sorry my apologies One before enough I just need the points you knowAnd I need to take more letters to make the sand should go through so it’s up
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the area of the surface of the swimming pool is 210 feet . what is the length d of the deep end ( in feets )?
zlopas [31]
<span>this is how i did it
 10(9)(d)= 210
  90d= 210
  d=2.3 feet.</span>
3 0
3 years ago
Brainliest if it is right
cupoosta [38]

Answer:

17.8

Step-by-step explanation:

All you have to do is 8.9 x 2 = 17.8

HOPE HIS HELPS

6 0
2 years ago
Read 2 more answers
your patient has a 2500 cc bag of irrigation solution hanging, and 750 cc of fluid has been infused. what percentage of irrigati
nlexa [21]

Answer:  30%

Step-by-step explanation:

Given : Patient has a 2500 cc bag of irrigation solution hanging.

Irrigation has been infused = 750cc

Then, the percentage of irrigation solution has been infused :

\dfrac{\text{ fluid infused}}{\text{Total irrigation solution}}\times100\\\\=\dfrac{750}{2500}\times100\\\\= 30\%

Hence, the percentage of irrigation solution has been infused = 30%

6 0
3 years ago
What is the value of 4p − 2, when p = 8
ddd [48]
If P=8, Then you would plug in 8 for P. 

4(8)-2 = 30 

Hope this helps :)
4 0
4 years ago
Read 2 more answers
Please help!!!! the question is in screenshot
andreev551 [17]

Answer:

-\cos nw_0t

Step-by-step explanation:

We can use the double angle identity for sine.

\sin (A+B)=\sin A \cos B+\sin B\cos A

The given expresion is

\sin (nw_0t-90)

We apply the identity to get:

\sin (nw_0t-90)=\sin nw_0t \cos 90-\cos nw_0t \sin 90

We simplify to obtain;

\sin (nw_0t-90)=\sin nw_0t (0)-\cos nw_0t (1)

This simplifies to:

\sin (nw_0t-90)=-\cos nw_0t The correct answer is D

8 0
3 years ago
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