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qaws [65]
4 years ago
12

There are 134 third graders and 167 fourth graders at the annual school and family picnic. the number of students is 7 times the

number of adults.
Each picnic table can seat 9 people. How many picnic tables will need to be set up fr the picnic? SHOW YOUR WORK
Is your answer reasonable?
Show or explain how to check your answer.
Mathematics
1 answer:
grandymaker [24]4 years ago
4 0
I got 39 tables.
134+167=301
301/7=43
Total amount of people =344
344/9=38.222 which you would round to 39 tables
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At a picnic there were 3 times as many adults as children and twice as many women as men. If there was a total of x men, women,
Lisa [10]

Answer:

I believe the answer is c.) x=4

Step-by-step explanation:

I saw this on a webpage:

The moment we see “x,” we can consider picking numbers. The key here is contemplating how complicated the number should be. Swim with the current – let the question tell you. A quick look at the answer choices reveals that x could be something simple. Ultimately, we’re just dividing this value by 2, 3, 4, 5, or 6.

Keeping this in mind, let’s think about the first line of the question. If there are 3 times as many adults as children, and we’re keeping things simple, we can say that there are 3 adults and 1 child, for a total of 4 people. So, x = 4.

Now, we know that among our 3 adults, there are twice as many women as men. So let’s say there are 2 women and 1 man. Easy enough. In sum, we have 2 women, 1 man, and 1 child at this picnic, and a total of 4 people. The question is how many men are there? There’s just 1! So now we plug x = 4 into the answers and keep going until we find x = 1. Clearly x/4 will work, so C is our answer. The key was to let the question dictate our approach rather than trying to impose an approach on the question.

7 0
3 years ago
Read 2 more answers
A rectangular garden has dimensions of 100 feet by 10 feet. Next season, the garden is decreased to 2/5 of its size. What is the
mina [271]

Answer:

40 feet by 4 feet

Step-by-step explanation:

Given length (l) = 100 feet

width (w) = 10 feet

As mentioned in the question the size of garden is decreased to 2/5 of its size. <u>It will effect the length and width with the same proportion.</u>

So,

New length = 100 * 2/5 = 40 feet

New width  = 10 * 2/5 = 4 feet

Therefore, the scale of new drawing would be 40 feet by 4 feet

4 0
3 years ago
Can somebody help outtt ?? pleasee
OleMash [197]

Answer:

y=71

x=109

Step-by-step explanation:

7 0
3 years ago
I need help finding the area
aniked [119]
<h3>Given :</h3>
  • Base of triangle = 7 yd
  • Height of triangle = 10 yd

\\  \\

<h3>To find:</h3>
  • Area of triangle

\\  \\

We know:-

When base and height of triangle is given we use this formula:

\bigstar \boxed{ \rm Area \: of \: triangle =  \frac{base \times height}{2} }

\\  \\

So:-

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{base \times height}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 10}{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times2 }{2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times\cancel2 }{\cancel2}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =  \dfrac{7 \times 5 \times1 }{1}  \\

\\  \\

\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5

\\  \\

\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2}  \\

\\  \\

\therefore  \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} {  \red{\bf{yd} }^{ \red2} }}

\\  \\

<h3>know more :-</h3>

\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}]

7 0
2 years ago
How can knowing the gcf and lcm help you when you add subtract and multiply fractions?
Maksim231197 [3]
<span>In order to add and subtract fractions, we must be able to find a <u>common denominator</u>.
The LCD, or least common denominator, is the LCM of the denominators. Once we've added, subtracted or multiplied fractions, we often have to simplify the fraction.
In order to do this, we divide the numerator and denominator by their GCF. This means we must be able to find the LCM and GCF in order to work with fractions.</span>
4 0
3 years ago
Read 2 more answers
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