Ask question

Ask question

All categories

1 year ago

6

Joshua is a year older than his sister McKay. The product of their ages is 33 more than 7 times Joshua’s age. How old are Joshua

and McKay?

1 answer:

joja [24]1 year ago

6 0

Answer:

Joshua is 11 and Mckay is 10.

You might be interested in

Determine the X- and Y- intercepts for the graph defined by the given equation. Y= -8

Cloud [144]

Y = -8 simply means for every x coordinate the y coordinate is -8, therefore it creates a horizontal line at y = -8.

X intercepts are when y = 0. Y intercepts are when x = 0.

In this case of the line, y = -8 there is no x intercept because y doesn’t equal 0.

However there is a y intercept at (0,-8) because y is -8 for every input including 0.

If you have any other questions feel free to ask.

4 0

2 years ago

Read 2 more answers

What is 7*-8? my calculator wont work because I cant do problems with negative # on it.

Jet001 [13]

7 x -8 = -56
Hope this helps! :-)

3 0

3 years ago

Read 2 more answers

In a certain study, the chance of encountering a car crash on the roadstudy, the chance of encountering a car crash on the road

pshichka [43]

10% as a decimal (a value between 0 and 1) is 0.1

8 0

3 years ago

Use the graph below to answer the following question:

larisa [96]

ANSWER

B) -1

EXPLANATION

From the graph,

f(1)=3 and f(4)=0.

The average rate of change from x=1 to x=4 of this function is,

$= \frac{f(4) - f(1)}{4 - 1}$

Substitute the functional values

$= \frac{0 - 3}{3}$

Simplify

$= \frac{-3}{3} = -1$

The correct choice is .

5 0

3 years ago

Read 2 more answers

1 calcule o valor das expressões A) 2x+(3.4)²+(7.7) B) 3x+(2.6)+(8.8)² C)7.6+(28.3)+(4)² D)7x-(7.8)+(9:3)

I am Lyosha [343]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

Given:

$A) \ \ 2x+(3.4)^2+(7.7) \\\\B) \ \ 3x+(2.6)+(8.8)^2\\\\C)\ \ 7.6+(28.3)+(4)^2 \\\\D)\ \ 7x-(7.8)+(9:3)$

For point A:

$\to 2x+(3.4)^2+(7.7)\\\\\to 2x+(11.56)+(7.7)\\\\\to 2x+19.26\\\\$

For point B:

$\to 3x+(2.6)+(8.8)^2\\\\\to 3x+(2.6)+77.44\\\\\to 3x+80.04$

For point C:

$\to \ 7.6+(28.3)+(4)^2 \\\\\to \ 7.6+(28.3)+16 \\\\\to \ 7.6+44.3 \\\\\to 51.9$

For point D:

$\to 7x-(7.8)+(9:3)\\\\\to 7x-(7.8)+ \frac{9}{3}\\\\\to 7x- \frac{23.4+9}{3}\\\\\to 7x- \frac{32.4}{3}\\\\\to 7x- 10.8$

3 0

2 years ago