v = 1/3Bh
Divide both sides by h.
v/h = 1/3B
Multiply both sides by 3.
3v/h = B
The area of a rectangle, which I'm assuming it is, is A= lw. Where "l" is length and "w" is width.
Answer:
First, we know that:
cot(x) = cos(x)/sin(x)
csc(x) = 1/sin(x)
I can't know for sure what is the exact equation, so I will assume two cases.
The first case is if the equation is:
if we replace cot(x) and csc(x) we get:
Now let's we can rewrite this as:
We can't simplify it more.
Second case:
If the initial equation was
Then if we replace cot(x) and csc(x)
This is equal to:
And we know that:
sin^2(x) + cos^2(x) = 1
Then:
sin^2(x) - 1 = -cos^2(x)
So we can replace that in our equation:
Answer:
y-2=1/3(x+3)
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(4-2)/(3-(-3))
m=2/(3+3)
m=2/6
simplify
m=1/3
y-y1=m(x-x1)
y-2=1/3(x-(-3))
y-2=1/3(x+3)
Answer:
Graph the polynomial in order to determine the intervals over which it is increasing or decreasing. Increasing on: (1,∞) ( 1 , ∞ ). Decreasing on: (−∞,1) ( - ∞ , 1 ).
Step-by-step explanation: