Look at the picture.
1)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
2)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
The square (call it
) has one vertex at the origin (0, 0, 0) and one edge on the y-axis, which tells us another vertex is (0, 3, 0). The normal vector to the plane is
, which is enough information to figure out the equation of the plane containing
:

We can parameterize this surface by

for
and
. Then the flux of
, assumed to be
,
is



Answer:
C. 303,000 Joules
Step-by-step explanation:
1. use abcos(theta)
a=50
b=7000
theta=30 degrees
2. (50)(7000)cos(30)=303,000
#5 is 96 because it is congruent to the one on top