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3 years ago

Round 3.995 to the nearest hundredth

Mathematics

2 answers:

Lera25 [3.4K]3 years ago

3 0

Answer: 4.00

Step-by-step explanation:

UNO [17]3 years ago

3 0

Answer:

3.99

Step-by-step explanation:

the hundreths place is the second place after the decimsl point.

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Pllllllllllllllllllllleasee one guys i neeed ur help one

Svetllana [295]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Let's solve ~

Calculate discriminant :

$\qquad \sf \dashrightarrow \: 3 {x}^{2} + 6x - 1$

a = 3
b = 6
c = 1

$\qquad \sf \dashrightarrow \: discriminant = {b}^{2} - 4ac$

$\qquad \sf \dashrightarrow \: d = (6) {}^{2} - (4 \times 3 \times 1)$

$\qquad \sf \dashrightarrow \: d = 36 - 12$

$\qquad \sf \dashrightarrow \: d = 24$

$\qquad \sf \dashrightarrow \: \sqrt {d} = 2 \sqrt{6}$

Now, let's calculate it's roots ( x - intercepts )

$\qquad \sf \dashrightarrow \: x = \cfrac{ - b \pm \sqrt{d} }{2a}$

$\qquad \sf \dashrightarrow \: x = \cfrac{ - 6\pm 2 \sqrt{6} }{2 \times 3}$

$\qquad \sf \dashrightarrow \: x = \cfrac{ - 6\pm 2 \sqrt{6} }{6}$

So, the intercepts are :

$\qquad \sf \dashrightarrow \: x = \cfrac{ - 6 - 2 \sqrt{6} }{6}$

and

$\qquad \sf \dashrightarrow \: x = \cfrac{ - 6 + 2 \sqrt{6} }{6}$

5 0

2 years ago

Read 2 more answers

For each level of precision, find the required sample size to estimate the mean starting salary for a new CPA with 95 percent co

Rzqust [24]

Answer:

(a) Margin of error ( E) = $2,000 , n = 54

(b) Margin of error ( E) = $1,000 , n = 216

(c) Margin of error ( E) = $500 , n= 864

Step-by-step explanation:

Given -

Standard deviation $\sigma$ = $7,500

$\alpha$ = 1 - confidence interval = 1 - .95 = .05

$Z_{\frac{\alpha}{2}}$ = $Z_{\frac{.05}{2}}$ = 1.96

let sample size is n

(a) Margin of error ( E) = $2,000

Margin of error ( E) = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

E = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$E^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{2000^{2}} \times 7500^{2}$

n = 54.0225

n = 54 ( approximately)

(b) Margin of error ( E) = $1,000

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

1000 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$1000^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{1000^{2}} \times 7500^{2}$

n = 216

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

500 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$500^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{500^{2}} \times 7500^{2}$

n = 864

7 0

3 years ago

Help me please i need your helpp

Inga [223]

Answer:

D) -2

Step-by-step explanation:

to identify the slope of a line written in slope-intercept form, it would be

the coefficient of the 'x' term

5 0

2 years ago

Data Set #1

Harman [31]

Answer:

The data table is attached below.

Step-by-step explanation:

The average of a set of data is the value that is a representative of the entire data set.

The formula to compute averages is:

$\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}$

Compute the average for drop 1 as follows:

$\bar x_{1}=\frac{1}{3}\times[10+11+9]=10$

Compute the average for drop 2 as follows:

$\bar x_{2}=\frac{1}{3}\times[29+31+30]=30$

Compute the average for drop 3 as follows:

$\bar x_{3}=\frac{1}{3}\times[59+58+61]=59.33$

Compute the average for drop 4 as follows:

$\bar x_{4}=\frac{1}{3}\times[102+100+98]=100$

Compute the average for drop 5 as follows:

$\bar x_{5}=\frac{1}{3}\times[122+125+127]=124.67$

The data table is attached below.

3 0

3 years ago

If you have 1-cup servings of juice to 30 people, how many whole gallons of juice will you need?

Ratling [72]

Answer:

2 gallons

Step-by-step explanation:

there are 16 cups in a gallon. if you have 30 cups for people, do $30/16=1.875$ which you cant have 0.875 gallons of juice, so you need to round it to two gallons.

3 0

3 years ago

Read 2 more answers