Answer:
Step-by-step explanation:
the perimeter is : p = 2(x+y)..... x : width y : length
you have the system ; 2(x+y) = 252.......(1)
x = (2/7) y ...........(2)
y > x ....(3)
Substitute x = (2/7) y into (1) and simplifiy and solve for y :
(2/7) y + y = 126
(2y+7y)/7 = 126
9y = 882
y = 98 m ( the length )
P(t) = P₀ e^(kt)
<span>Where P₀ is the initial population, </span>
<span>P(t) is the population after "t" time. </span>
<span>t is your rate (can be hours, days, years, etc. in this case, hours) </span>
<span>k is the growth constant for this particular problem. </span>
<span>So using the information given, solve for k: </span>
<span>P₀ = 2000 </span>
<span>P(4) = 2600 </span>
<span>P(t) = P₀ e^(kt) </span>
<span>2600 = 2000e^(k * 4) </span>
<span>1.3 = e^(4k) </span>
<span>Natural log of both sides: </span>
<span>ln(1.3) = 4k </span>
<span>k = ln(1.3) / 4 </span>
<span>Now that we have a value for "k", use that, the same P₀, then solve for P(17): </span>
<span>P(t) = P₀ e^(kt) </span>
<span>P(17) = 2000 e^(17ln(1.3) / 4) </span>
<span>Using a calculator to get ln(1.3) then to simplify from there, we get: </span>
<span>P(17) ≈ 2000 e^(17 * 0.262364 / 4) </span>
<span>P(17) ≈ 2000 e^(4.460188 / 4) </span>
<span>P(17) ≈ 2000 e^(1.115047) </span>
<span>P(17) ≈ 2000 * 3.0497 </span>
<span>P(17) ≈ 6099.4 </span>
<span>Rounded to the nearest unit: </span>
<span>P(17) ≈ 6099 bacteria hope i could help =)))</span>
Let C be the number of cats and B be the number of birds.
Each cat has 4 legs while each bird has 2 legs. Thus,
4C + 2B = 22
2B = 22 - 4C
Each cat and each bird has 2 eyes
2C + 2B = 16
Substituting 2B
2C + 22 - 4C = 16
2C = 6
C = 3
2B = 22 - 4(3)
B = 5
2 cats and 5 birds
No.
The three angles of a triangle need to add up to 180 degrees, this means no one angle can be 180 degrees.
