The range of the given function is represented by {-6,-4,2}.
<h3>Domain and Range</h3>
The domain of a function is the set of input values for which the function is real and defined. In the other words, when you define the domain, you are indicating for which values x the function is real and defined.
While the domain is related to the values of x, the range is related to the possible values of y that the function can have.
Here, you need to replace the given domain values in the equation: f(x)=x-4. The question gives that the domain is represented by: -2 ,0 ,2 .
Thus,
For x=-2, you have:
f(x)= x-4
f(x)= -2-4
f(x)= -6
For x=0, you have:
f(x)= 0-4
f(x)= 0-4
f(x)= -4
For x=2, you have:
f(x)= x-4
f(x)= 2-4
f(x)= -2
Therefore, the range of the given function is {-6,-4,2}
Learn more about the range here:
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Answer:
below
Step-by-step explanation:
a. in cursive writing as your signature
Answer:
y = 5x - 3
Step-by-step explanation:
As we move from the point (-2, -13) to the point (1, 2), we see the x-value (the 'run') increasing by 3 and the y-value (the 'rise') increasing by 15. Therefore the slope of the line passing thru these two points is m = rise / run = 15/3, or m = 5.
Using the slope-intercept formyula y = mx + b, we find the y-intercept as follows, using 1 for x, 2 for y and 5 for m:
2 = 5(1) + b, or
b = -3
Then the desired equation is
y = 5x - 3
Quadrant of after 360 would the first quadrant.
As the if the cycle of all four quadrant is completed than it becomes zero(0) .
eg.cos 405
cos(360+45)
cos(0+45)
cos45=1/2^1/2
