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3 years ago

Please help for online school

Mathematics

1 answer:

Stels [109]3 years ago

4 0

Answer:

Step-by-step explanation:

The diagram shows that the one triangle can be divided into two equal right triangles. Because of this, you can use the Pythagorean Theorem to solve this problem. a and b are the two sides of the angles, and c is the hypotenuse.

The given lengths are 5 as the hypotenuse and 3 as one length. (You have 3 as a given length because the two triangles have a length of 6 on one side. 6/2 = 3)

a² + b² = c²

a² = c² - b²

a² = 5² - 3²

a² = 25² - 9²

a² = 16

a = 4

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The help is needed for these times

rosijanka [135]

Answer:

This be soooo hard ;w;

Step-by-step explanation:

.w.

3 0

3 years ago

PLEASE HELP!!!

AfilCa [17]

Answer:

$h=\dfrac{10\sqrt{3}}{2}=5\sqrt{3}\ cm.$

$JP=5\sqrt{3}\ cm$

Step-by-step explanation:

Connecting points O and E and points O and J, we get triangle EOJ. This triangle is equilateral triangle, because OJ=OE=JE=r=10 cm.

Since EP⊥IJ, then segment JP is the height of the triangle EOJ.

The height of the equilateral triangle can be found using formula

$h=\dfrac{a\sqrt{3}}{2},$

where a is the side length.

So,

$h=\dfrac{10\sqrt{3}}{2}=5\sqrt{3}\ cm.$

Therefore JP is 5√3 cm

3 0

3 years ago

If 14y - 4 = 24y + 26 , then 12y =

harkovskaia [24]

Solutions

To solve the equation we have to isolate 12y

$14y - 4 = 24y + 26

-4 - 26 = 24y - 14y

-30 = 10y

10y = -30

y =- -30/10

y = -3

12y =12/-3

12y = -36

Therefore, 12y = -36$

4 0

3 years ago

Read 2 more answers

For each pair of similar figures, find the ratio of the area of the first figure to the area of the second.

Hitman42 [59]

answer:

$\frac{4}{9}$

explanation:

the area of the larger square is 36 (6*6), and the area of the smaller square is 16 (4*4). to find the ratio of the area, simply just put 16 over 36 and simplify.

$\frac{16}{36} = \frac{4}{9}$

if this helped, please consider giving brainliest !

7 0

3 years ago

1. Make sure your answers and work is SHOWN please and steps are in order.

JulijaS [17]

Been a while since I've done synthetic division.

1a. Let's assume that's supposed to be an equals sign

p(x) = 2x⁴ - 3x³ - 6x² + 5x + 6

possible rational roots have factors of 6 in the numerator and of 2 in the denominator. We'll only worry about negative numerators.

Factors of six: 1,2,3,6, and we don't forget -1,-2,-3,-6

Factors of 2: 1,2

Possible rational roots:

(dividing by 1:) 1,-1,2,-2,3,-3,6,-6

(dividing by 2:) 1/2, -1/2 (2/2=1 is a duplicate, don't have to repeat it), 3/2, -3/2

Possible rational roots: 1,-1,2,-2,3,-3,6,-6, 1/2, -1/2, 3/2, -3/2

Synthetic division, trying x=1,

1 | 2 -3 -6 5 6

2 -1 -7 -2

2 -1 -7 -2 4

Got a remainder of 4, so 1 isn't a root;

Trying x=-1

-1 | 2 -3 -6 5 6

-2 5 1 -6

2 -5 -1 6 0

Zero remainder, found a root, x=-1. This division says

(2x⁴ - 3x³ - 6x² + 5x + 6) / (x + 1) = 2x³ - 5x² - x + 6

Same set of rational roots on the cubic, we continue with x=2

2 | 2 -5 -1 6

4 -2 -6

2 -1 -3 0

Another zero remainder, x=2 is a root. We're left with 2x² - x - 3 = 0, which factors as

(2x - 3)(x + 1) = 0

That's a second factor of x+1. Our final factorization is

2x⁴ - 3x³ - 6x² + 5x + 6 = (x + 1)²(x-2)(2x - 3)

Fourth degree with a positive leading coefficient so goes to +infinity at both ends. Double zero at x=-1, so it's tangent there, just touching the x axis, then down through x=3/2 and up through x=2.

I'll leave the actually sketching and the other two polynomials to you -- that took some time.

4 0

3 years ago