The acceleration of the SRB and main engine during the first 2.0 minutes of flight is 52.16 m/s².
The given parameters;
- <em>initial velocity of the engine, u = 1341 m/s</em>
- <em>final velocity of the engine, v = 7600 m/s</em>
- <em>time of motion, t = 2 minutes = 2 x 60 s = 120 s</em>
The acceleration of the SRB and main engine is calculated as follows;
Thus, the acceleration of the SRB and main engine during the first 2.0 minutes of flight is 52.16 m/s².
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Answer:
Meter (m)
Explanation:
The wavelenght of a light wave is a measure of the distance between two successive crests (or two successive troughs) of a light wave.
Since the SI units for the distance is the meter (m), then the SI unit for the wavelength is also the meter (m).
Wavelength is related to the frequency of the light wave by:
where
c is the speed of light
f is the frequency of the light
Well, Godess, that's not a simple question, and it doesn't have
a simple answer.
When the switch is closed . . .
"Conventional current" flows out of the ' + ' of the battery, through R₁ ,
then through R₂ , then through R₃ . It piles up on the right-hand side of
the capacitor (C). It repels the ' + ' charges on the left side of 'C', and
those flow into the ' - ' side of the battery. So the flow of current through
this series circuit is completely clockwise, around toward the right.
That's the way the first experimenters pictured it, that's the way we still
handle it on paper, and that's the way our ammeters display it.
BUT . . .
About 100 years after we thought that we completely understand electricity,
we discovered that the little tiny things that really move through a wire, and
really carry the electric charge, are the electrons, and they carry NEGATIVE
charge. This turned our whole picture upside down.
But we never changed the picture ! We still do all of our work in terms of
'conventional current'. But the PHYSICAL current ... the actual motion of
charge in the wire ... is all exactly the other way around.
In your drawing ... When the switch is closed, electrons flow out of the
' - ' terminal on the bottom of the battery, and pile up on the left plate of
the 'C'. They repel electrons off of the right-side of 'C', and those then
flow through R₃ , then through R₂ , then through R₁ , and finally into the
' + ' terminal on top of the battery.
Those are the directions of 'conventional' current and 'physical' current
in all circuits.
In the circuit of YOUR picture that you attached, there's more to the story:
Battery current can't flow through a capacitor. Current flows only until
charges are piled up on the two sides of 'C' facing each other, and then
it stops.
Wait a few seconds after you close the switch in the picture, and there is
no longer any current in the loop.
To be very specific and technical about it . . .
-- The instant you close the switch, the current is
(battery voltage) / (R₁ + R₂ + R₃) amperes
but it immediately starts to decrease.
-- Every (C)/((R₁ + R₂ + R₃) seconds after that, the current is
e⁻¹ = about 36.8 %
less than it was that same amount of time ago.
Now, are you glad you asked ?
Answer:
(a). The change in the average kinetic energy per atom is 
.
(b). The change in vertical position is 2413 m.
Explanation:
Given that,
Mass = 40.0 u
The increased temperature from 286 K to 362 K.
(a). We need to calculate the change in the average kinetic energy per atom
Using formula of kinetic energy
Put the value into the formula
(b). The change in potential energy of the container due to change in the vertical position
We need to calculate the change in vertical position
Using formula of potential energy
Hence, (a). The change in the average kinetic energy per atom is .
(b). The change in vertical position is 2413 m.
Answer:
gravity i think hope this helps
Explanation:
