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Naily [24]
3 years ago
11

Question is in PNG please someone help!

Physics
1 answer:
zhuklara [117]3 years ago
3 0

Answer:

2.a.i think it's heat and kinetic

2.b.i think kinetic

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How do simple machines make work easier?
castortr0y [4]
 work is defined as force acting on an object in the direction of motion, a machine makes work easier to perform by accomplishing one or more of the following functions: transferring a force from one place to another, changing the direction of a force, increasing the magnitude of a force, or increasing the distance or speed of a force
<span>D. They increase the distance over which a force is applied.</span>
3 0
3 years ago
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A crate is sliding down a ramp that is inclined at an angle 30.6 ° above the horizontal. The coefficient of kinetic friction bet
Vlada [557]

Answer:1.95 m/s^2

Explanation:

Given

inclination \theta =30.6^{\circ}

coefficient of kinetic friction \mu =0.36

As crate is moving Down therefore friction will oppose the motion

using FBD

mg\sin \theta -f_r=ma

f_r=\mu N

f_r=\mu mg\cos \theta

mg\sin \theta -\mu mg\cos \theta =ma

a=g\sin \theta -\mu g\cos \theta

a=g(\sin (30.6)-0.36\cdot \cos (30.6))

a=9.8\times 0.199

a=1.95 m/s^2          

6 0
3 years ago
a flat bed truck is carrying a crate up a 10.0 hill inn the picture. the coefficent of the static friction between the truck bed
almond37 [142]

Answer:

a = 0.711 m/s^2

Explanation:

As we know that truck is moving up the hill

So here we have two forces on the crate placed on the truck

1) gravitational force along the floor

2) Friction force along the floor

Now here if the truck is moving with maximum possible acceleration so that there is no slipping of the crate

So here we will have

\mu mg cos\theta - mgsin\theta = ma

a = \mu g cos\theta - g sin\theta

a = (0.25)(9.81)cos10 - 9.81 sin10

a = 0.711 m/s^2

7 0
4 years ago
9 The friction between the car and the mud is equivalent to the__________________.
kakasveta [241]
Answer: e. None

Explanation: when the car goes into the muddy area, then the friction force on the tire is too small so the wheels are turned and slipped. Friction in this case is beneficial
5 0
3 years ago
500 nm light passes through a circular aperture that has a diameter d = 30.0 μm. A diffraction pattern forms on a screen 350 mm
larisa86 [58]

Complete Ques

Answer:

The value is A =  0.00214 \  m^2

Explanation:

From the question we are told that

    The wavelength is  \lambda  =  500 \  nm =  500 *10^{-9}  \  m

     The diameter of the aperture is d = 30 \mu m  =  30*10^{-6} \ m

     The distance of the screen from the aperture is D =  350 \ m m  =  0.350 \  m

Generally the distance from the center the the edge of the central bright fringe is magmatically reparented as

          y  =  \frac{m *  \lambda *  D}{d}

Generally m =  1 because after the central bright fringe we have the first order fringe

So

          y  =  \frac{1  *  500 *10^{-9} *  0.350}{30*10^{-6}}

=>       y  =0.00583 \ m

Generally the area of the central bright fringe

           A =  2 \pi * y^2

=>        A =  2 * 3.142  * 0.00583^2

=>        A =  0.00214 \  m^2

         

3 0
3 years ago
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