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Shalnov [3]
3 years ago
8

A gas cylinder contains argon atoms (m=40.0 u). The temperature is increased from 286 K (13°C) to 362 K (89°C) (a) What is the c

hange in the average kinetic energy per atom? eV (b) The container is resting on a table in the Earth's gravity. Find the change in the vertical position of the container that produces the same change in the average energy per atom found in part
Physics
1 answer:
Rama09 [41]3 years ago
4 0

Answer:

(a). The change in the average kinetic energy per atom is 1.57\times10^{-21}\ eV.

(b). The change in vertical position is 2413 m.

Explanation:

Given that,

Mass = 40.0 u

The increased temperature from 286 K to 362 K.

(a). We need to calculate the change in the average kinetic energy per atom

Using formula of kinetic energy

\Delta K.E=\dfrac{3}{2}k\Delta t

Put the value into the formula

\Delta K.E=\dfrac{3}{2}\times1.38\times10^{-23}\times(362-286)

\Delta K.E=1.57\times10^{-21}\ eV

(b). The change in potential energy of the container due to change in the vertical position

We need to calculate the change in vertical position

Using formula of potential energy

\Delta U=mg\Delta h

\Delta h =\dfrac{\Delta U}{mg}

\Delta h=\dfrac{1.57\times10^{-21}}{40.0\times1.66\times10^{-27}\times9.8}

\Delta h=2412.7=2413\ m

Hence, (a). The change in the average kinetic energy per atom is 1.57\times10^{-21}\ eV.

(b). The change in vertical position is 2413 m.

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Where distance is measured in meters and time in seconds.

The average velocity is equal to the position variation divided by the time variation.

V_{avg}=\frac{Displacement}{Time} = Δx / Δt = \frac{x2-x1}{t2-t1}

For the first time interval :

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The average velocity for this interval is :

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The time variation is t2 - t1 = 7 s - 1 s = 6 s

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The position variation is x2 - x1 = 701 m - (-1 m) = 702 m

The average velocity is

\frac{702m}{6s}=117\frac{m}{s}

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