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xeze [42]
3 years ago
7

$700 at 8% for 6 years

Mathematics
1 answer:
olga55 [171]3 years ago
3 0

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$700\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ t=years\dotfill &6 \end{cases} \\\\\\ I=(700)(0.08)(6)\implies I=336~\hfill \stackrel{\stackrel{balance}{700+336}}{1036}

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A shipment To a warehouse consists of 4500 MP3 players the manager chooses a random sample of 50 MP3 players and finds that 7 ar
riadik2000 [5.3K]

Answer:

<u>630</u> MP3 players are likely to be defective.

Step-by-step explanation:

Given:

A shipment to a warehouse consists of 4500 MP3 players the manager chooses a random sample of 50 MP3 players and finds that 7 are defective.

Now, to find the MP3 players which are likely to be defective.

Let the defective MP3 players be x.

Total MP3 players = 4500.

In sample of 50 MP3 players 7 are defective.

Now, setting the proportion:

If, 50 is equivalent to 7.

Then, 4500 is equivalent to x.

Now, to solve using cross multiplication method:

\frac{50}{7} =\frac{4500}{x}

<em>By cross multiplying we get:</em>

<em />50x=31500<em />

<em>Dividing both sides by 50 we get:</em>

x=630.

Therefore, 630 MP3 players are likely to be defective.

5 0
3 years ago
Part 2 - Find the error(s) and solve the problem correctly.
Aneli [31]

Answer:

Step-by-step explanation:

6 0
2 years ago
A one-topping pizza costs $15.00. Each additional topping costs $1.25. Let x be the number of additional toppings. You have $20
pantera1 [17]
So,

Our total will be equal to 20.  If we want 1 additional topping, we will have an additional $1.25.  <span>If we want 2 additional toppings, we will have an additional $2.50.  So we can just multiply the number of additional toppings by 1.25 to get the additional amount.

1.25x

However, you will have already spent $15.

1.25x + 15 = 20

This is option B.

P.S. You will be able to put exactly 4 additional toppings.</span>
3 0
3 years ago
Read 2 more answers
which shows the students in order from greatest test score to lease test score Alex 0.95 Octavia 16/20 Tonya 9/10 Wilson 0.87 ​
Nonamiya [84]

Answer:

Alex (0.95), Tonya (0.90), Wilson (0.87), Octavia (0.80)

Step-by-step explanation:

To solve this, we have to convert all of the scores into either a decimal or a fraction. In this case, I will be solving all of them into decimals since it is easier.

Alex: 0.95

Octavia: 16/20 = 0.80

Tonya: 9/10 = 0.90

Wilson: 0.87

Therefore, we can order these from greatest score to least score.

Alex (0.95), Tonya (0.90), Wilson (0.87), Octavia (0.80)

4 0
3 years ago
A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in
erica [24]

Answer:

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

n=10 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =0.0217 represent the sample variance

\sigma^2_0 =0.12^2= 0.0144 represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 0.0144

Alternative hypothesis: \sigma^2 \neq 0.0144

The statistic can be calculated like this;

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0
3 years ago
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