Answer:
Explanation:
try
clc
clear
close all
x=linspace(0,2*pi,7);
z=cos(pi.*x./3)
% the output on mine is to 4 decimals so it looks a bit different than what the output on your example is , but, I think if you change the format to decimal 2 it will look the same :)
Answer:
In Java:
import java.util.*;
public class Main{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String isbn;
System.out.print("First 1:2 digits: ");
isbn = input.nextLine();
if(isbn.length()==12){
int chksum = 0;
for(int i = 0; i<12;i++){
if((i+1)%2==0){ chksum+= 3 * Character.getNumericValue(isbn.charAt(i)); }
else{ chksum+=Character.getNumericValue(isbn.charAt(i)); } }
chksum%=10;
chksum=10-chksum;
if(chksum==10){
System.out.print("The ISBN-13 number is "+isbn+"0");}
else{
System.out.print("The ISBN-13 number is "+isbn+""+chksum); } }
else{
System.out.print("Invalid Input");
} }}
Explanation:
See attachment for explanation where comments are used to explain each line
Answer:
yes i agree with that the answer is in fact true
Explanation:
follow my in sta gram at grac.ehihi
