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motikmotik
3 years ago
8

Write a scenario that could be represented by this equation: 3/4x = 12

Mathematics
1 answer:
Aneli [31]3 years ago
8 0

Answer:

x=1 or x=16

Step-by-step explanation:

3/4x = 12      or        0.75x = 12

3/4x/3/4 = 12/3/4     or     0.75x/0.75 = 12/0.75

x=12/1 / 3/4

x= 4/4

x = 1                           or       x = 16

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Answer:

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Step-by-step explanation:

5 0
3 years ago
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What are the roots of x in -10x^2 + 12x − 9 = 0
taurus [48]

Answer:

No roots

Step-by-step explanation:

the discriminant Δ = 12²-4×(-10)×(-9) = -216

since ∆ is negative then the equation -10x^2 + 12x − 9 = 0 has no solution .

8 0
4 years ago
Write a division expression with a quotient that is: greater than 8÷0.001 less than 8÷0.001 between 8÷0.001 and 8÷110 does one b
Anna71 [15]

Answer:

  • 9÷0.001 is greater than 8÷0.001.
  • 7÷0.001 is less than 8÷0.001.
  • 8÷0.002 lie between 8÷0.001 and 8÷110.

Step-by-step explanation:

  • The division expression which is greater than 8÷0.001 is:

9÷0.001

Since, the numerator of the number 9÷0.001 is greater than 8÷0.001. and as their denominator is same.

so, the number whose numerator is greater than the other will result in the overall number to be greater.

  • The division expression which is less than 8÷0.001 is 7÷0.001.

Since, for two numbers with same denominator the number whose numerator is smaller is smaller than the other.

  • The division expression that lie between 8÷0.001 and 8÷110 is: 8÷0.002.

Since 8÷0.002 is greater than 8÷110, as for two numbers with same numerator but different denominator the number whose denominator is greater is a smaller number.

similarly 8÷0.002 is smaller than 8÷0.001.





8 0
3 years ago
A random sample is selected from a population with mean μ = 102 and standard deviation σ = 10. For which of the sample sizes wou
chubhunter [2.5K]

Answer:

Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the \bar X with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

\bar X \sim N (\mu ,\frac{\sigma}{\sqrt{n}} )

Based on this rule we can conclude:

a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440

Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean

for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed

Step-by-step explanation:

For this case we know that for a random variable X we have the following parameters given:

\mu = 102, \sigma =10

Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the \bar X with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

\bar X \sim N (\mu ,\frac{\sigma}{\sqrt{n}} )

Based on this rule we can conclude:

a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440

Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean

for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed

8 0
3 years ago
20/10= determine the whole number
USPshnik [31]
20/10 is the same as 

20 ÷ 10

The answer is 2.
I hope this helps! :)
5 0
4 years ago
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