Answer:
b
Step-by-step explanation:
Answer:
No roots
Step-by-step explanation:
the discriminant Δ = 12²-4×(-10)×(-9) = -216
since ∆ is negative then the equation -10x^2 + 12x − 9 = 0 has no solution .
Answer:
- 9÷0.001 is greater than 8÷0.001.
- 7÷0.001 is less than 8÷0.001.
- 8÷0.002 lie between 8÷0.001 and 8÷110.
Step-by-step explanation:
- The division expression which is greater than 8÷0.001 is:
9÷0.001
Since, the numerator of the number 9÷0.001 is greater than 8÷0.001. and as their denominator is same.
so, the number whose numerator is greater than the other will result in the overall number to be greater.
- The division expression which is less than 8÷0.001 is 7÷0.001.
Since, for two numbers with same denominator the number whose numerator is smaller is smaller than the other.
- The division expression that lie between 8÷0.001 and 8÷110 is: 8÷0.002.
Since 8÷0.002 is greater than 8÷110, as for two numbers with same numerator but different denominator the number whose denominator is greater is a smaller number.
similarly 8÷0.002 is smaller than 8÷0.001.
Answer:
Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the
with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

Based on this rule we can conclude:
a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440
Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean
for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed
Step-by-step explanation:
For this case we know that for a random variable X we have the following parameters given:

Since we can't assume that the distribution of X is the normal then we need to apply the central limit theorem in order to approximate the
with a normal distribution. And we need to check if n>30 since we need a sample size large as possible to assume this.

Based on this rule we can conclude:
a. n = 14 b. n = 19 c. n = 45 d. n = 55 e. n = 110 f. n = 440
Only for c. n = 45 d. n = 55 e. n = 110 f. n = 440 we can ensure that we can apply the normal approximation for the sample mean
for n=14 or n =19 since the sample size is <30 we don't have enough evidence to conclude that the sample mean is normally distributed
20/10 is the same as
20 ÷ 10
The answer is 2.
I hope this helps! :)