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Andrews [41]
2 years ago
12

miranda types at a rate of 48 words per minute. which equation describes how long it will take her to type a 3000 word essay?

Mathematics
2 answers:
snow_lady [41]2 years ago
4 0

Answer:

62.5

Step-by-step explanation:

3000/48 well it would be 62.5 minutes per hour for each 48 words

62.5 x 48=3000

Sav [38]2 years ago
3 0

Answer:

3000=48x where x= minutes.

Step-by-step explanation:

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the point (4,0) lies on a circle with the center at the orgin. what is the area of the circle to the nearsest hundreth?
kvasek [131]

Answer:

50.27 units²

Step-by-step explanation:²

The standard equation of a circle with center at the origin is x² + y² = r², where r is the radius.  Substituting 4 for x and 0 for y yields 4² + 0² = r², so we see immediately that r = 4 units.

The formula for the area of a circle is A = πr².

Here, with r = 4, the area is A = π(4 units)² = 16π units², or

50.27 units² to the nearest hundredth.

3 0
3 years ago
Write in slope intercept form the equation of a line that has the slope of 1/3 and the y- intercept of 5.
ludmilkaskok [199]

Answer:

y = 1/3x + 5

Step-by-step explanation:

Slope intercept form is y = mx + b

m is the slope

b is the y intercept

plug your number in

y = 1/3x + 5

5 0
3 years ago
Carlie is out shopping and finds a 198.00 hat that is on sale for 90% of its original price. What is the new cost of the item? C
lbvjy [14]

I believe the new cost of the item is $19.80

5 0
3 years ago
Given a rectangle with length of (2x+9)cm and width of (3x+1)cm.Two squares, each with sides x cm is removed from the rectangle.
il63 [147K]

Answer: The length is 13cm and the width is 7cm

Step-by-step explanation:

For a rectangle of length L and width W, the area is:

A = W*L

In this case we have:

L = (2*x + 9) cm

W=(3*x + 1) cm

Then the area of the rectangle is:

A = (2*x + 9)*(3*x + 1) cm^2

A = (6*x^2 + 2*x + 27*x + 9) cm^2

A = (6*x^2 + 29*x + 9) cm^2

now we remove two squares with sides of x cm

The area of each one of these squares is (x cm)*(x cm)  = x^2 cm^2

Then the area of the figure will be:

area = (6*x^2 + 29*x + 9) cm^2 - (2*x^2 ) cm^2

area = (4*x^2 + 29*x + 9) cm^2

Now we know that the area of this shape is 83 cm^2, then we need to solve:

83 cm^2 = (4*x^2 + 29*x + 9) cm^2

0 =  (4*x^2 + 29*x + 9) cm^2 - 83 cm^2

0 = (4*x^2 + 29*x - 74) cm^2

Then we need to solve:

0 = 4*x^2 + 29*x - 74

Here we can use Bhaskara's equation, the solutions of this equation are given by:

x = \frac{-29 \pm \sqrt{29^2 - 4*4*(-74)}  }{2*4} = \frac{-29 \pm 45}{8}

Then the two solutions are:

x = (-29 - 45)/8 = -9.25  (for how the length and width are defined, we can not have x as a negative number, then this solution can be discarded).

The other solution is:

x = (-29 + 45)/8 = 2

x = 2

Then the length and width of the rectangle are:

Length = (2*2 + 9)cm = 13 cm

Width = (3*2 + 1)cm = 7cm

4 0
2 years ago
Find and compare the median and
Over [174]

Answer:

Median= $2.45/2

=$1.225

Mode= $2.87

3 0
3 years ago
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