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IRINA_888 [86]
3 years ago
13

Determine whether set B is a subset of set A. A={0,1,2,3,4} B={1,2}

Mathematics
1 answer:
forsale [732]3 years ago
4 0

Answer:

B is a subset of  set A  because every element of set B is contained in set A

Step-by-step explanation:

The answer to this question is:

B is a subset of  set A  because every element of set B is contained in set A.

We can denote it as B⊆A

<u>Subset:</u>

A subset is a set of elements that are also in another set.  Another way to define a subset is: B is a subset of A if every element of B is contained in A.

It is denoted by B⊆A ....

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Given the following statistics for women over the age of 50 entering our medical clinic: 1% actually have breast cancer 90% of t
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4 0
4 years ago
Find k so that the distance from (–1, 1) to (2, k) is 5 units. k= k= *there are two solutions for 2*
dalvyx [7]

Answer:

k = -3

k =5

Step-by-step explanation:

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d = 5\\(-1,1) =(x_1,y_1)\\(2,k)=(x_2,y_2)\\

5=\sqrt{\left(2-\left(-1\right)\right)^2+\left(k-1\right)^2}\\\\\mathrm{Square\:both\:sides}:\quad 25=k^2-2k+10\\25=k^2-2k+10\\\\\mathrm{Solve\:}\:25=k^2-2k+10:\\k^2-2k+10=25\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\k^2-2k+10-25=25-25\\k^2-2k-15=0\\\\\mathrm{Solve\:by\:factoring}\\\\\mathrm{Factor\:}k^2-2k-15:\quad \left(k+3\right)\left(k-5\right)\\\mathrm{Solve\:}\:k+3=0:\quad k=-3\\

\mathrm{Solve\:}\:k-5=0:\quad k=5\\\\k =5 , k=-3

7 0
3 years ago
Read 2 more answers
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