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IRINA_888 [86]
3 years ago
13

Determine whether set B is a subset of set A. A={0,1,2,3,4} B={1,2}

Mathematics
1 answer:
forsale [732]3 years ago
4 0

Answer:

B is a subset of  set A  because every element of set B is contained in set A

Step-by-step explanation:

The answer to this question is:

B is a subset of  set A  because every element of set B is contained in set A.

We can denote it as B⊆A

<u>Subset:</u>

A subset is a set of elements that are also in another set.  Another way to define a subset is: B is a subset of A if every element of B is contained in A.

It is denoted by B⊆A ....

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Lisa purchases a professional racing bicycle that sells for $3,000, including tax. It requires an 18.5% down payment. How much i
matrenka [14]

Answer: 3,0080

Step-by-step explanation:

3 0
3 years ago
Ms.beatly Is trying to get healthy and starts running in the morning.She is able to run 5 miles in 45 minutes how many how many
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Answer:

1. 9 minutes

Step-by-step explanation:

1. If she runs 5 miles in 45 minutes, you have 5 miles = 45 minutes. If you divide both sides of this ratio by 5, you get 1 miles = 9 minutes

2. Find out how many each person sells per week:

Emily: 4 boxes = 2 weeks

divide both sides by 2

2 boxes = 1 week

Jose: 9 boxes = 3 weeks

divide both sides by 3

3 boxes = 1 week

This means that jose sells more, because 3 boxes > 2 boxes

6 0
3 years ago
What is the mode of the following numbers?<br> 3,7, 5, 2, 5, 5, 2,5
tangare [24]

The mode is 5.ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

8 0
2 years ago
Read 2 more answers
7) PG &amp; E have 12 linemen working Tuesdays in Placer County. They work in groups of 8. How many
BabaBlast [244]

Part A

Since order matters, we use the nPr permutation formula

We use n = 12 and r = 8

_{n}P_{r} = \frac{n!}{(n-r)!}\\\\_{12}P_{8} = \frac{12!}{(12-8)!}\\\\_{12}P_{8} = \frac{12!}{4!}\\\\_{12}P_{8} = \frac{12*11*10*9*8*7*6*5*4*3*2*1}{4*3*2*1}\\\\_{12}P_{8} = \frac{479,001,600}{24}\\\\_{12}P_{8} = 19,958,400\\\\

There are a little under 20 million different permutations.

<h3>Answer: 19,958,400</h3>

Side note: your teacher may not want you to type in the commas

============================================================

Part B

In this case, order doesn't matter. We could use the nCr combination formula like so.

_{n}C_{r} = \frac{n!}{r!(n-r)!}\\\\_{12}C_{8} = \frac{12!}{8!(12-8)!}\\\\_{12}C_{8} = \frac{12!}{4!}\\\\_{12}C_{8} = \frac{12*11*10*9*8!}{8!*4!}\\\\_{12}C_{8} = \frac{12*11*10*9}{4!} \ \text{ ... pair of 8! terms cancel}\\\\_{12}C_{8} = \frac{12*11*10*9}{4*3*2*1}\\\\_{12}C_{8} = \frac{11880}{24}\\\\_{12}C_{8} = 495\\\\

We have a much smaller number compared to last time because order isn't important. Consider a group of 3 people {A,B,C} and this group is identical to {C,B,A}. This idea applies to groups of any number.

-----------------

Another way we can compute the answer is to use the result from part A.

Recall that:

nCr = (nPr)/(r!)

If we know the permutation value, we simply divide by r! to get the combination value. In this case, we divide by r! = 8! = 8*7*6*5*4*3*2*1 = 40,320

So,

_{n}C_{r} = \frac{_{n}P_{r}}{r!}\\\\_{12}C_{8} = \frac{_{12}P_{8}}{8!}\\\\_{12}C_{8} = \frac{19,958,400}{40,320}\\\\_{12}C_{8} = 495\\\\

Not only is this shortcut fairly handy, but it's also interesting to see how the concepts of combinations and permutations connect to one another.

-----------------

<h3>Answer: 495</h3>
5 0
2 years ago
Should this be labeled as non-linear? If not, what is the rate of change? Please show your work, I’m very confused.
il63 [147K]

Answer:

This is not linear.

Step-by-step explanation:

<h2>As you can see the difference between x and y decreases the higher we go.</h2>

5 0
3 years ago
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