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oksian1 [2.3K]
2 years ago
6

26 is what percent of 325

Mathematics
2 answers:
Inga [223]2 years ago
7 0

Answer:

8%

Step-by-step explanation:

anyanavicka [17]2 years ago
4 0
Answer would be 8 percent
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Plz help i beg i will give 20 points and give brainlist
Lubov Fominskaja [6]
It’s a 90 degree angle. So the equation so be 28+2x =90 and find x from there.


28+2x=90
-28 -28
2x= 62
x=31
4 0
2 years ago
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a formula for finding the perimeter of a rectangle is p=2L+2W if you know the perimeter (p) and width (w) of a rectangle which f
lbvjy [14]

Step-by-step explanation:

You can first multiply the width by two. Then you subtract that from you perimeter to figure out your length. Whatever number you get divide it by two and there's your length.

Example:

Perimeter =30 Width=5

5 times 2= 10

30-10=20

20/2=10

So your length equals 10.

I hope this helps!

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2 years ago
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Can you help me please?
SVETLANKA909090 [29]

Answer:

its 34

Step-by-step explanation:

8 0
3 years ago
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The probability Jake will arrive at school on time is<br> 0.87. What is the complement of this?
3241004551 [841]

Answer:sorry need some points for help

Sorry so sorry

Step-by-step explanation:

Sorry

5 0
3 years ago
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Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am
zheka24 [161]

SOLUTION

We have been given the equation of the decay as

\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}

So we are looking for the time

Plugging the values into the equation, we have

\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}

Taking Ln of both sides, we have

\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}

Hence the answer is 4308 to the nearest year

8 0
9 months ago
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