Help me oo000-00000of

What is the slope of the line that passes through the points (-3, 5) and (1, 7)?

just olya [345]

$\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{7}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{7-5}{1-(-3)}\implies \cfrac{7-5}{1+3}\implies \cfrac{2}{4}\implies \cfrac{1}{2}$

4 0

3 years ago

Read 2 more answers

Question 1 (Essay Worth 10 points)

il63 [147K]

Answer:

Part A. x = 1/26 Part B. x = 1/50

Step-by-step explanation:

Solve for x:

26 x = 1

Divide both sides by 26:

Answer: x = 1/26

___________________

Solve for x:

50 x = 1

Divide both sides by 50:

Answer: x = 1/50

8 0

3 years ago

Determine whether the equation is always sometimes or never true 2(5x+4)=10x+6

Usimov [2.4K]

This equation is NEVER true. Let's solve the equations algebraically by applying the Distributive Property of Multiplication and transposing the terms across the equality sign. The solution is as follows:

<span>2(5x+4)=10x+6
10x + 8 = 10x + 6
10x - 10x = 6 - 8
0 = -2

Therefore, it is not true.</span>

3 0

3 years ago

8u/u^2-18u+81 subtract 72/u^2-18u+81

Karo-lina-s [1.5K]

Your question is:
$\frac{8u}{u^2-18u+81} -\frac{72}{u^2-18u+81}$
Then, the above formula equate:

$\frac{8u-72}{u^2-18u+81}$
Factor out 8 from the numerator we get:
$\frac{u-9}{u^2-18u+81}$
Factorization of the denominator:
$\frac{u-9}{(u-9)^2}$
Simplifying the numerator and the denominator by (u-9) we get:
$\frac{1}{(u-9)}$

6 0

3 years ago

Write an equation for each context. Draw a model first if necessary, and make sure you define your variable and what it represen

Bad White [126]

Answer:

(a)$2248.8

(b) 14, 28, 16 and 7 candies

(c) $79

Step-by-step explanation:

(a) the model can be represented by the nth term of an arithmetic progression

L = a + (n-1)d

L= the amount in his account after 6 month; $12484

a= the amount in his account six month before; $1240

n = 6, being the sixth month of his deposit

d = the amount deposited monthly

12484 = 1240 + 5d:

12484-1240 = 5d

5d= 11244

d = 2248.8

(b) let the 1st box contain = x

2nd = 2x; 3rd = x + 2, 4th = 1/4(2x)

Hence; x + 2x + x +2 + 1/4(2x) = 65

4x + x/2 = 65-2

9x/2 = 63 ; 9x = 126. ; x = 14

(c) Each player gets a racket (r) and a can (c) of balls

The 5 players get in all 5 racket + 5 cans since Simon is a member

Therefore, 5r + 5c = 415

But each can cost $4,

5r + 5* 4 = 415; 6r = 415-20

5r = 395 ; r = 395/5

r = $ 79

The racket cost $79 each.

8 0

3 years ago