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qwelly [4]
2 years ago
14

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each sine or cosine value to its equi

valent measure
Cos(57=
Sin(43)=
Cos(43)=
Sin(32)=

A: cos(137)
B: cos(47)
C: sin(16)
D: sin(106)
E: sin(33)
F: cos(58)
G: sin(123)
Mathematics
1 answer:
VARVARA [1.3K]2 years ago
7 0

Sines and cosines are trigonometric identities

The corresponding match of the sine or cosine values are:

  • Cos(57) = Sin(33)
  • Sin(43) = Cos(47)
  • Cos(43) = Sin(47)
  • Sin(32) = Cos(58)

<h3>How to determine the sine and cosine values</h3>

Given that:

\sin(a) = \cos(b)

Then:

a + b = 90

This means that, angles a and b are opposite values

For cos(57),

The sine value is: sin(33)

This is so because:

57 + 33 = 90

When the above formula is applied to the remaining functions, we have:

sin(43) = cos(47)

cos(43) = sin(47)

sin(32) = cos(58)

Read more about sine and cosine ratios at:

brainly.com/question/12172664

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andrew-mc [135]

Step-by-step explanation:

2( - 3x - 6) \\   - 6x + 12

3 0
3 years ago
Read 2 more answers
Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
Can someone help on these two thanks
forsale [732]

Answer:

C & D

Step-by-step explanation:

For the first one, all you have to do is count how many numbers are behind the decimal point and add them together (1 + 3 = 4)  and then you count up the decimal 4 places which would be 0.7416.

For the second one, you divide the days by miles (18/3=6) then you divide the 6 by 72 which would be 12.

Hope this helps!

3 0
3 years ago
What is the slope of the line 1/2y=-5x-37
DIA [1.3K]

Answer:

Slope = - 10

Step-by-step explanation:

y=mx+n, m=slope

1/2y=-5x-37 /*2

y=-5*2x-37*2

y=-10x-74

Slope =- 10

4 0
3 years ago
Consider a sample with a mean of 30 and a standard deviation of 5. Use chebyshev's theorem to determine the percentage of data w
RSB [31]

With the help of Chebyshev's theorem, the percentage of data between 5 to 45 is 89%.

<h3>What is Chebyshev's theorem?</h3>

The minimum percentage of observations that are within a given range of standard deviations from the mean is calculated using Chebyshev's Theorem.

Numerous other probability distributions can be applied to this theorem.

Chebyshev's Inequality is another name for Chebyshev's Theorem.

One of many theorems established by Russian mathematician Pafnuty Chebyshev is known as Chebyshev's theorem.

According to Bertrand's postulate, there is a prime between n and 2n for every n.

So, the percentage of data within 15 to 45 is:

In this instance, we're looking for numbers between 15 and 45.

Since 30 -3*5 = 20 and 30 + 3*5 = 45, we are therefore within 3 deviations of the mean. So, since k = 3, we can find the percent as follows:

% = (1 - 1/3²) × 100 = 88.88% = 89%

Therefore, with the help of Chebyshev's theorem, the percentage of data between 5 to 45 is 89%.

Know more about Chebyshev's theorem here:

brainly.com/question/28482338

#SPJ4

5 0
1 year ago
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