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jekas [21]
3 years ago
6

Which shape is constructed only of triangles

Mathematics
2 answers:
Juliette [100K]3 years ago
7 0
Deltahedron, hope this helps :)
Goshia [24]3 years ago
4 0

Pyramid is 1 of many that can.

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Find csc x if sin x + cot x cos x =√3.
Oksi-84 [34.3K]

Answer:

The answer is (d) ⇒ cscx = √3

Step-by-step explanation:

∵ sinx + (cotx)(cosx) = √3

∵ sinx + (cosx/sinx)(cosx) = √3

∴ sinx + cos²x/sinx = √3

∵ cos²x = 1 - sin²x

∴ sinx + (1 - sin²x)/sinx = √3 ⇒ make L.C.M

∴ (sin²x + 1 - sin²x)/sinx = √3

∴ 1/sinx = √3

∵ 1/sinx = cscx

∴ cscx = √3

7 0
3 years ago
A circular plate has a circumference of 119.32cm. Calculate the diameter.
bekas [8.4K]

Answer:

Diameter is equal to 38 cm.

Step-by-step explanation:

We know that the circumference equals  πd (where d is the diameter).

If we round the value of π to 3.14 then we will get...

πd = 119.32

(3.14)d = 119.32

d = 119.32 / 3.14

d = 38 cm

Therefore the diameter is equal to 38 cm

3 0
3 years ago
0.3 ÷ 42 Will someone please help me with the method on how to do this it is very hard.
slamgirl [31]

The answer is 1/140

Work Shown

0.3 / 42

Convert and Rewrite

3/10 x 1/42

Reduce The Numbers With the greatest Common divisor 3

1/10 x 1/14

Multiply the fractions

1/140 or

AlTernative Form  0.007114285 , -1 over 140


I Hope This Help

-Dante

3 0
3 years ago
If sin(A+B)=1/2 & sin(A-B)=1/3 find sin(2A)
timofeeve [1]

Answer:

sin(2A) = (2√2 + √3) / 6

Step-by-step explanation:

2A = (A+B) + (A−B)

sin(2A) = sin((A+B) + (A−B))

Angle sum formula:

sin(2A) = sin(A+B) cos(A−B) + sin(A−B) cos(A+B)

sin(2A) = 1/2 cos(A−B) + 1/3 cos(A+B)

Pythagorean identity:

sin(2A) = 1/2 √[1 − sin²(A−B)] + 1/3 √[1 − sin²(A+B)]

sin(2A) = 1/2 √(1 − 1/9) + 1/3 √(1 − 1/4)

sin(2A) = 1/2 √(8/9) + 1/3 √(3/4)

sin(2A) = 1/3 √2 + 1/6 √3

sin(2A) = (2√2 + √3) / 6

6 0
3 years ago
given triangle UVW is congruent to triangle TSR find the values of x (12x-7), y (5y-33), and z (3z+14)
timama [110]

Answer:

Step-by-step explanation:

Find the image attached. For two triangles to be congruent, then the sides of UVW is equal to that of TSR

From the diagram given

TR = UW

Given

TR = 50

UW = 3z+14

Equate and find z;

3z+14 = 50

3z = 50-14

3z = 36

z = 36/3

z = 12

VW = RS

Given

VW = 27

RS = 5y - 33

Equate

5y-33 = 27

5y = 27+33

5y = 60

y = 60/5

y = 12

Also TS = UV

TS = 53

UV = 12x+7

Equate:

12x-7 = 53

12x = 53+7

12x = 60

x = 60/12

x = 5

Hence x = 5, y = 12 and z = 12

3 0
3 years ago
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