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2 years ago

Help me please thank you 3.solve for x and y also

Mathematics

1 answer:

ahrayia [7]2 years ago

4 0

Answer:

y=1 x=-16 these are the answers

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2. Solve each given equation and show your work. Tell whether it has one solution, an infinite number of

marin [14]

Answer:

a. infinite solutions, answer is x = 30, identity equation

b. no solution, a contradiction equation

c. no solution, a contradiction equation

Step-by-step explanation:

3 0

3 years ago

1. 2 qt =<br> pt please help me with this I need so much help

Olegator [25]

Can you give more information

3 0

3 years ago

Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

$\int \:8\sec \left(t\right)dt$

$=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|$

now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

5 0

3 years ago

Hich values are solutions to the inequality?

Troyanec [42]

$2r\leq3r-8\\0\leq r-8\\8\leq r\\r\geq8$

So, in the list of numbers, 8 and 9 are solutions

7 0

3 years ago

Read 2 more answers

Line CD contains points A (4, 6) and B (−2, 6). The slope of line CD is (4 points)

lbvjy [14]

Answer:

Step-by-step explanation:

To find the slope, we use the formula

m= (y2-y1)/(x2-x1)

= (6-6)/(-2-4)

= 0/-6

8 0

3 years ago