Answer:
0.59% probability that exactly 97 out of 100 randomly sampled American adults had chickenpox during childhood.
Step-by-step explanation:
For each person, there are only two possible outcomes. Either they have had chickenpox, or they have not. The probability of a person having had chickenpox is independent from other people. So we use the binomial probability distribution to solve this problem.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
90% of Americans have had chickenpox by the time they reach adulthood.
This means that 
Suppose we take a random sample of 100 American adults. Is the use of the binomial distribution appropriate for calculating the probability that exactly 97 out of 100 randomly sampled American adults had chickenpox during childhood
This is
when
. So


0.59% probability that exactly 97 out of 100 randomly sampled American adults had chickenpox during childhood.
Answer:
Since, Robin is twice as old as Earl,
Thus, the ratio of the age of robin and earl = 2 : 3
Let the age of robin = 2x and the age of earl = 3x
Where x is any number,
According to the question,
3×Age of Adam = 2x + 6
Age of Adam = 1/3(2x+6)
Also, Age of Adam = Age of earl - 8
⇒ 1/3(2x+6) = 3x - 8
⇒ 2x + 6 = 9x - 24
⇒ -7x = - 30
⇒ x = 30/7
Hence, the age of Robin = 2x = 2×30/7 = 60/7 years
The age of Earl = 3x = 3×30/7=90/7 years
The age of Adam = 34/7 years
It is the vendor that sells 1.5 L for $2.70
There are 12 face cards and 4 aces to choose from. For the first card, the probability of drawing a face is

. Then the probability of drawing an ace second is

.
So the probability of drawing these two particular cards in the given order is