Composite.
Because the definition of them is, <span>A prime number has only two factors: 1 and itself. A composite number has more than two factors. The number 1 is neither prime nor composite. The prime numbers between 2 and 31 are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29 and 31 since each of these numbers has only two factors, itself and 1.
Hope this helped!!! :)
-Ginger
</span>
Answer:
29 hours
Step-by-step explanation:
If he earned $404.70 per 19 hours, you do 404.70/19 to figure out the amount he earns per hour. 404.7/19 is 21.3. He earns $21.3 per hour. to solve, you find how many times 21.3 goes into 617.7 or 617.7/21.3. That is 29. He needs to work 29 hours to earn $617.70
Answer:
B. Sine.
Step-by-step explanation:
We need to find the value of x which is opposite to the given angle (50 degree). Also we are given the length of the hypotenuse.
Sine = opposite / hypotenuse so we would use the sine.
Its worth committing this mnemonic to memory, which helps to find the required trig ratio:
SOH-CAH-TOA.
SineOpposite/Hypotenuse- CosineAdjacent/Hypotenuse-TangentOpposite/Adjacent.
Lagrange multipliers:







(if

)

(if

)

(if

)
In the first octant, we assume

, so we can ignore the caveats above. Now,

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of

.
We also need to check the boundary of the region, i.e. the intersection of

with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force

, so the point we found is the only extremum.
You need to do 10 divided by 4. Each friend would get 2.5 pounds of a nut.