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Darina [25.2K]
3 years ago
6

WILL GIVE BRAINLIEST!

Mathematics
1 answer:
SOVA2 [1]3 years ago
7 0

Answer:

The magnitude of the net gravitational force acting on Ify is 9.1 newtons.

Ify is getting pulled in a direction of 6.2 radians.

Step-by-step explanation:

The vector g = (9,-1)   describes the net gravitational force acting on Ify.

We can find the magnitude of  g, using the Pythagorean theorem.

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Taz packs 15 sweaters in boxes. Each box can hold 4 sweaters.
stira [4]

Answer:3 and 3/4 :)

Step-by-step explanation: 15/4= 3 R 3 3 and 3/4

6 0
3 years ago
Help please ive been stuck for way to long 37 points no joke
Lelu [443]
-7/15.
You multiply the numerator and denominator to get -21/45. To simplify, divide each by the greatest common factor, which is three, to get -7/15.
3 0
3 years ago
louise skip counts by 4 on a number line to find 5 x 4 how many jumps should she draw in the number line
saul85 [17]
<h3>Answer:</h3>

It depends:

  • 4 if she starts at 4
  • 5 if she starts at 0
<h3>Explanation:</h3>

Louise needs to end up a total of 5 times 4 away from zero.

If she starts at 4, which is 1 times 4, then she needs to jump 4 more times, to 2, 3, 4, 5 times 4.

If she starts at 0, then she needs to jump 5 times to 1, 2, 3, 4, 5 times 4. (The values at the end of each jump will be {4, 8, 12, 16, 20}.)

4 0
3 years ago
In the diagram, CE=12 units and BE=5 units.
LekaFEV [45]

Answer:

AE = CE —> identical

So ; AE= 12 units

I hope I helped you^_^

4 0
3 years ago
Which of the following are identities? check all that apply.
Feliz [49]

Answer: (a), (b), (c), and (d)

Step-by-step explanation:

Check the options

(a)\\\Rightarrow [\sin x+\cos x]^2=\sin ^2x+\cos ^2x+2\sin x\cos x\\\Rightarrow [\sin x+\cos x]^2=1+2\sin x\cos x\\\Rightarrow \Rightarrow [\sin x+\cos x]^2=1+\sin 2x

(b)\\\Rightarrow \sin (6x)=\sin 2(3x)\\\Rightarrow \sin 2(3x)=2\sin (3x)\cos (3x)

(c)\\\Rightarrow \dfrac{\sin 3x}{\sin x\cos x}=\dfrac{3\sin x-4\sin ^3x}{\sin x\cos x}\\\\\Rightarrow 3\sec x-4\sin ^2x\sec x\\\Rightarrow 3\sec x-4[1-\cos ^2x]\sec x\\\Rightarrow  3\sec x-4\sec x+4\cos x\\\Rightarrow 4\cos x-\sec x

(d)\\\Rightarrow \dfrac{\sin 3x-\sin x}{\cos 3x+\cos x}=\dfrac{2\cos [\frac{3x+x}{2}] \sin [\frac{3x-x}{2}]}{2\cos [\frac{3x+x}{2}]\cos [\frac{3x-x}{2}]}\\\\\Rightarrow \dfrac{2\cos 2x\sin x}{2\cos 2x\cos x}=\dfrac{\sin x}{\cos x}\\\\\Rightarrow \tan x

Thus, all the identities are correct.

4 0
3 years ago
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