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2 years ago

Geometry: Help this makes no sense I don’t think there’s enough info needa find x

Mathematics

1 answer:

umka2103 [35]2 years ago

8 0

The answer should be 9sqrt2 because the equation for finding the legs on a 45-45-90 triangle is hypotenuse/sqrt2.

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An art teacher has 24 girls and 40 boys at a soccer camp. The campers will be divided into equal-sized groups. Each group will h

tresset_1 [31]

8 groups is what i suppose
Hope this helps!!! ;-)

5 0

3 years ago

A lift driver charges $5.25 for the first mile of the trip and$1.25 each mile after that. He charges the customer $24 for the ri

WARRIOR [948]

Answer: 15 miles

Step-by-step explanation:

The equation is 5.25+1.25x=24 where x is each additional mile so to solve for x it would be 1.25x=18.75 and divide both sides to solve for x

3 0

3 years ago

Read 2 more answers

From a height of 50 meters above sea level on a cliff, two ships are sighted due west. The angles of depression are 61° and 28°.

Olenka [21]

Answer:

The ships are 66 meters apart.

Step-by-step explanation:

For the sake of convenience, let us label ships A and B

As shown in the figure, the distances to the ships from right triangles.

The distance to the ship A is $d_1$ and it is given by

$tan (61^o)= \dfrac{50}{d_1}$

$d_1=\dfrac{50}{tan (61^o)}$

$\boxed{d_1= 27.71m}$

And the distance to the ship B is $d_2$ and is given by

$tan (28^o)= \dfrac{50}{d_2}$

$d_2=\dfrac{50}{tan (28^o)}$

$\boxed{ d_2=94.04m}$

Therefore, the distance $d$ between the ships A and B is

$d= d_2-d_1=94.04-27.7\\\\\boxed{d=66m}$

In other words, the ships are 66 meters apart.

8 0

3 years ago

Read 2 more answers

Help<br><br> Determine which equation is parallel to line jk and which is perpendicular to line jk.

alukav5142 [94]

Answer:

5x + 3y = 13 parallel.

6x - 10y = 7 perpendicular.

Step-by-step explanation:

Two lines with slopes $m_1$ and $m_2$ are parallel when $m_1=m_2$ and are perpendicular when $m_1*m_2=-1$

Now determine the slope of all the lines

The line jk passes through the points

(-5,5) and (1,-5) so its slope is

$\frac{-5-5}{1-(-5)}=\frac{-10}{6}=-\frac{5}{3}$

To determine the slope of the lines in the blue rectangles, isolate y from each one and the coefficient of x is the slope

5x-3y = 8 ------> y = (5/3)x + 8/3 ------> slope 5/3

Neither parallel nor perpendicular.

6x+10y = 11 ------> y = (-6/10)x + 11/10 = (-3/5)x + 11/10 ------> slope -3/5

Neither parallel nor perpendicular.

5x + 3y = 13 ------> y = (-5/3)x + 13/3 ------> slope -5/3

This line is parallel

6x - 10y = 7 ------> y = (6/10)x - 7/10 = (3/5)x -7/10 ------> slope 3/5

Since (-5/3)(3/5) = -1 this line is perpendicular.

8 0

3 years ago

At a large nursery, a border for a rectangular garden is being built. Designers want the border’s length to be twice as long as

sasho [114]

Let

x--------> the border’s length

y--------> the border’s width

P--------> perimeter of the border

we know that

x=5+y------> equation 1

P=2*[x+y]-----> P=2x+2y

P <=180 ft

(2x+2y) <= 180-------> equation 2

substitute the equation 1 in equation 2

2*[5+y]+2y <= 180

10+2y+2y <= 180

4y <= 180-10

4y <=170

y <=42.5 ft

the maximum value of the width is 42.5 ft

for y=42.5 ft

x=42.5+5------> x=47.5 ft

the answer is

the width of the border is less than or equal to 42.5 ft

7 0

3 years ago