We are given with the variable cost which is:
q = -20s + 400
The selling price is 's'. So, the profit can be represented by:
P = qs - q(12)
Subsituting:
P = (-20s + 400)s - 12 (-20s + 400)
P = -20s^2 + 640s - 4800
To optimize this, we must differentiate the equation and equate it to zero, so:\
dP/ds = -40s + 640 = 0
Solving for s,
s = 16
So, the selling price should be $16 to optimize the yearly profit.
Answer:
Help with what is it mental help? Or no cause I’ve dealt with that a lot
Step-by-step explanation:
S= savings before she bought the dress s - $55 would be her new balance after she bought the dress.
We could also talk about her savings now (after her purchase). If we let n=now
n + $55 would be her balance before she bought the dress.
The cost of delivering an item that weighs 4/5 of a pound?$21.60.
<h3>How to find the delivery cost?</h3>
Let x = the number of pounds
Thus, we can say that;
Cost = 25x * 1.08
Since we want to find the cost of delivering an item that weighs 4/5 of a pound, the we will put 4/5 for x to get;
Cost = (25 * 4/5) * 1.08
Cost = 20 * 1.08
Cost = 21.6
The delivery cost would be $21.60.
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